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df823f4c09
This allows rendering of a vertex directly, rather than just as an edge endpoint. They're currently drawn as small '+' signs. A round dot would be better, but the code is passing a list of line segments around, so this is simpler.
102 lines
4.2 KiB
C#
102 lines
4.2 KiB
C#
/*
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* Copyright 2018 faddenSoft
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS,
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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*/
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using System;
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using System.Diagnostics;
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namespace CommonUtil {
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public class RawData {
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/// <summary>
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/// Extracts an integer from the data stream. Integers less than 4 bytes wide
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/// are not sign-extended.
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/// </summary>
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/// <param name="data">Raw data stream.</param>
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/// <param name="offset">Start offset.</param>
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/// <param name="width">Word width, which may be 1-4 bytes.</param>
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/// <param name="isBigEndian">True if word is in big-endian order.</param>
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/// <returns>Value found.</returns>
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public static int GetWord(byte[] data, int offset, int width, bool isBigEndian) {
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if (width < 1 || width > 4 || offset + width > data.Length) {
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throw new ArgumentOutOfRangeException("GetWord(offset=" + offset + " width=" +
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width + "), data.Length=" + data.Length);
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}
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if (isBigEndian) {
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switch (width) {
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case 1:
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return data[offset];
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case 2:
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return (data[offset] << 8) | data[offset + 1];
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case 3:
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return (data[offset] << 16) | (data[offset + 1] << 8) | data[offset + 2];
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case 4:
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return (data[offset] << 24) | (data[offset + 1] << 16) |
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(data[offset + 2] << 8) | data[offset + 3];
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}
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} else {
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switch (width) {
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case 1:
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return data[offset];
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case 2:
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return data[offset] | (data[offset + 1] << 8);
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case 3:
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return data[offset] | (data[offset + 1] << 8) | (data[offset + 2] << 16);
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case 4:
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return data[offset] | (data[offset + 1] << 8) | (data[offset + 2] << 16) |
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data[offset + 3] << 24;
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}
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}
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throw new Exception("GetWord(): should not be here");
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}
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/// <summary>
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/// Fetches a two-byte little-endian value from a byte stream, advancing the offset.
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/// </summary>
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/// <param name="data">Byte stream.</param>
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/// <param name="offset">Initial offset. Value will be incremented by 2.</param>
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/// <returns>Value fetched.</returns>
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public static ushort FetchLittleUshort(byte[] data, ref int offset) {
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ushort val = (ushort)(data[offset] | (data[offset + 1] << 8));
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offset += 2;
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return val;
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}
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/// <summary>
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/// Compare parts of two arrays for equality.
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/// </summary>
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/// <remarks>
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/// We can do this faster with unsafe code. For byte arrays, see
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/// https://stackoverflow.com/q/43289/294248 .
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/// </remarks>
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/// <param name="ar1">First array.</param>
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/// <param name="offset1">Initial offset in first array.</param>
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/// <param name="ar2">Second array.</param>
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/// <param name="offset2">Initial offset in second array.</param>
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/// <param name="count">Number of elements to compare.</param>
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/// <returns>True if the array elements are equal.</returns>
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public static bool CompareArrays<T>(T[] ar1, int offset1, T[] ar2, int offset2,
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int count) {
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Debug.Assert(count > 0);
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for (int i = 0; i < count; i++) {
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if (!ar1[offset1 + i].Equals(ar2[offset2 + i])) {
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return false;
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}
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}
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return true;
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}
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}
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}
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