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6502bench/CommonUtil/BitTwiddle.cs
Andy McFadden cd23580cc5 Add junk/align directives
Sometimes there's a bunch of junk in the binary that isn't used for
anything.  Often it's there to make things line up at the start of
a page boundary.

This adds a ".junk" directive that tells the disassembler that it
can safely disregard the contents of a region.  If the region ends
on a power-of-two boundary, an alignment value can be specified.

The assembly source generators will output an alignment directive
when possible, a .fill directive when appropriate, and a .dense
directive when all else fails.  Because we're required to regenerate
the original data file, it's not always possible to avoid generating
a hex dump.
2019-10-18 21:00:28 -07:00

95 lines
3.7 KiB
C#

/*
* Copyright 2019 faddenSoft
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
using System;
namespace CommonUtil {
public class BitTwiddle {
/// <summary>
/// Returns the argument, rounded up to the next highest power of 2. If the argument
/// is an exact power of two, it is returned unmodified.
/// </summary>
public static int RoundUpPowerOf2(int val) {
val--; // handle exact power of 2 case; works correctly for val=0
return NextHighestPowerOf2(val);
}
/// <summary>
/// Returns the first power of 2 value that is higher than val. If the argument is
/// an exact power of two, the next power of 2 is returned.
/// </summary>
/// <remarks>
/// Classic bit-twiddling approach. I can't find a "count leading zeroes" function
/// in C# that turns into a CPU instruction; if we had that, we could just use 1<<N.
/// </remarks>
public static int NextHighestPowerOf2(int val) {
val |= val >> 1; // "smear" bits across integer
val |= val >> 2;
val |= val >> 4;
val |= val >> 8;
val |= val >> 16;
return val + 1;
}
/// <summary>
/// Returns an integer in which the only bit set is the least-significant set bit in
/// the argument.
/// </summary>
/// <remarks>
/// If you pass in 10110100, this will return 00000100.
///
/// Two's complement negation inverts and adds one, so 01100 --> 10011+1 --> 10100. The
/// only set bit they have in common is the one we want.
/// </remarks>
public static int IsolateLeastSignificantOne(int val) {
return val & -val;
}
/// <summary>
/// Returns the number of bits that are set in the argument.
/// </summary>
/// <remarks>
/// If you pass in 10110100, this will return 4.
///
/// This comes from http://aggregate.org/MAGIC/#Population%20Count%20(Ones%20Count) .
/// </remarks>
public static int CountOneBits(int val) {
// 32-bit recursive reduction using SWAR...
// but first step is mapping 2-bit values
// into sum of 2 1-bit values in sneaky way
val -= ((val >> 1) & 0x55555555);
val = (((val >> 2) & 0x33333333) + (val & 0x33333333));
val = (((val >> 4) + val) & 0x0f0f0f0f);
val += (val >> 8);
val += (val >> 16);
return (val & 0x0000003f);
}
/// <summary>
/// Returns the number of trailing zero bits in the argument.
/// </summary>
/// <remarks>
/// If you pass in 10110100, this will return 2.
///
/// Also from http://aggregate.org/MAGIC/ .
/// </remarks>
public static int CountTrailingZeroes(int val) {
// Lazy: reduce to least-significant 1 bit, subtract one to clear that bit and set
// all the bits to the right of it, then just count the 1s.
return CountOneBits(IsolateLeastSignificantOne(val) - 1);
}
}
}