diff --git a/lessons/lesson1a.txt b/lessons/lesson1a.txt index 6bbf287..3c8ea94 100644 --- a/lessons/lesson1a.txt +++ b/lessons/lesson1a.txt @@ -6,35 +6,35 @@ FDF0- 8 cout .eq $fdf0 0900- 11 * part 1 0900-A9 C1 12 lda #"A" ; spelling out "APPLE" 0902-20 F0 FD 13 jsr cout ; and outputting using -0905-A9 D0 14 lda #"P" ; the built-in monitor +0905-A9 F0 14 lda #"p" ; the built-in monitor 0907-20 F0 FD 15 jsr cout ; routines 090A-20 F0 FD 16 jsr cout ; directly printing -090D-A9 CC 17 lda #"L" ; one letter at a time +090D-A9 EC 17 lda #"l" ; one letter at a time 090F-20 F0 FD 18 jsr cout -0912-A9 C5 19 lda #"E" +0912-A9 E5 19 lda #"e" 0914-20 F0 FD 20 jsr cout 0917-60 21 rts 0918- 22 0918- 23 * part 2 0918-A2 05 24 ldx #$05 ; the number of letters -091A-BD 24 09 25 more2 lda text,x ; place in acc like before +091A-BD 23 09 25 more2 lda text-1,x ; place in acc like before 091D-20 F0 FD 26 jsr cout ; print it -0920-CA 27 dex ; decrease x-index register by one (1) -0921-10 F7 28 bpl more2 ; still have more to print +0920-CA 27 dex ; decrease x-index register by one (1) +0921-D0 F7 28 bne more2 ; still have more to print 0923-60 29 done rts -0924-C5 CC D0 D0 - C1 30 text .hs c5ccd0d0c1 ; ELPPA (backwards APPLE) +0924-E5 EC F0 F0 + C1 30 text .hs e5ecf0f0c1 ; elppA (backwards Apple) 0929- 31 0929- 32 * part 3 0929-A2 00 33 ldx #$00 ; load our index with zero 092B-BD 36 09 34 more3 lda text2,x ; grab the text form below 092E-F0 F3 35 beq done ; if it's 00, no more text 0930-20 F0 FD 36 jsr cout ; print it -0933-E8 37 inx ; get next letter +0933-E8 37 inx ; get next letter 0934-D0 F5 38 bne more3 ; branch if x is not equal to zero (0) -0936-C1 D0 D0 CC - C5 00 39 text2 .hs c1d0d0ccc500 ; text in order (APPLE) -093C- 40 +0936-C1 F0 F0 EC + E5 00 39 text2 .hs c1f0f0ece500 ; text in order (Apple) +093C- 40 ; with trailing zero (0) 093C- 41 * part 4 0000- 42 zploc .eq $00 ; define our zero-page address 093C-A9 36 43 lda #text2 ; put the pointer in zero-page @@ -45,7 +45,8 @@ FDF0- 8 cout .eq $fdf0 0946-B1 00 48 more4 lda (zploc),y ; grab indirect index to our text 0948-F0 D9 49 beq done ; if zero (0) then exit 094A-20 F0 FD 50 jsr cout ; print it! -094D-C8 51 iny ; increment our index to get the next letter +094D-C8 51 iny ; increment our index to get the next letter 094E-D0 F6 52 bne more4 ; branch of y is not zero (0) 0950- 53 0950- 54 PROG_END +