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Add scan function for disassembly
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@ -124,12 +124,8 @@ mos6502_dis_operand(FILE *stream, int addr_mode, vm_16bit value)
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* opcode maps to.
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*/
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void
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mos6502_dis_instruction(FILE *stream, vm_8bit opcode)
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mos6502_dis_instruction(FILE *stream, int inst_code)
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{
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int inst_code;
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inst_code = mos6502_instruction(opcode);
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// Arguably this could or should be done as fputs(), which is
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// presumably a simpler output method. But, since we use fprintf()
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// in other places, I think we should continue to do so. Further, we
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@ -184,3 +180,79 @@ mos6502_dis_expected_bytes(vm_8bit opcode)
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// trickery. Let's fearfully return zero!
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return 0;
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}
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/*
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* Scan the segment (with a given address) and write the opcode at that
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* point to the given file stream. This function will also write an
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* operand to the file stream if one is warranted. We return the number
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* of bytes consumed by scanning past the opcode and/or operand.
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*/
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int
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mos6502_dis_scan(FILE *stream, vm_segment *segment, int address)
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{
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vm_8bit opcode;
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vm_16bit operand;
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int expected;
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// The next byte is assumed to be the opcode we work with.
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opcode = vm_segment_get(segment, address);
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// And given that opcode, we need to see how many bytes large our
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// operand will be.
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expected = mos6502_dis_expected_bytes(opcode);
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// The operand itself defaults to zero... in cases where this
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// doesn't change, the instruction related to the opcode will
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// probably not even use it.
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operand = 0;
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// And we need to skip ahead of the opcode.
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address++;
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switch (expected) {
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case 2:
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// If we have a two-byte operand, then the first byte is the
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// MSB and our operand will need to shift it 8 positions to
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// the left before it can be OR'd.
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operand |= vm_segment_get(segment, address) << 8;
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address++;
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// Note we fall through here to the next case...
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case 1:
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// If it's a one-byte operand, then this byte should occupy
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// the LSB space which simply requires we OR the byte
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// directly in. If this is part of a two-byte operand, then
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// the same logic still applies.
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operand |= vm_segment_get(segment, address);
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address++;
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// And, in any other case (e.g. 0), we are done; we don't
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// read anything, and we leave the operand as it is.
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default:
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break;
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}
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// Let's print out to the stream what we have so far. First, we
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// indent by four spaces.
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fprintf(stream, " ");
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// Print out the instruction code that our opcode represents.
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mos6502_dis_instruction(stream, mos6502_instruction(opcode));
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// Let's "tab" over; each instruction code is 3 characters, so let's
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// move over 5 spaces (4 spaces indent + 1, just to keep everything
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// aligned by 4-character boundaries).
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fprintf(stream, " ");
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// Print out the operand given the proper address mode.
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mos6502_dis_operand(stream, mos6502_addr_mode(opcode), operand);
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// And let's terminate the line.
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fprintf(stream, "\n");
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// The expected number of bytes here is for the operand, but we need
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// to add one for the opcode to return the true number that this
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// opcode sequence would consume.
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return expected + 1;
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}
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