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More details in the ADC test
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@ -6,23 +6,85 @@
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TestSuite(mos6502_arith, .init = setup, .fini = teardown);
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/*
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* ADC is a deceptively simple instruction. It works like this:
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*
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* A = A + DATA + C
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*
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* If D = 1, then ADC works in an entirely different manner, treating
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* the input as BCD (Binary-Coded Decimal).
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*
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* Z = 1 if RESULT = 0
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* N = 1 if RESULT has BIT 7 high
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* V = 1 if (A ^ DATA) has BIT 7 high AND (A ^ RESULT) has BIT 7 high
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* C = 1 if (16-BIT) RESULT > 0xFF
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*/
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Test(mos6502_arith, adc)
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{
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cpu->A = 5;
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mos6502_handle_adc(cpu, 3);
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cr_assert_eq(cpu->A, 9);
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cpu->A = 0xfe;
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mos6502_handle_adc(cpu, 0x5);
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cr_assert_eq(cpu->A, (vm_8bit)(0xfe + 0x5));
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vm_8bit start = 30,
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main = 60,
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ztest = 0x100 - start,
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vtest = 0x80,
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ctest = 0xff;
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// Test with and without carry
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cpu->P |= MOS_CARRY;
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cpu->A = start;
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mos6502_handle_adc(cpu, main);
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cr_assert_eq(cpu->A, start + main + 1);
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cpu->P &= ~MOS_CARRY;
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cpu->A = 9;
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mos6502_handle_adc(cpu, 64);
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cr_assert_eq(cpu->A, 73);
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cpu->A = start;
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mos6502_handle_adc(cpu, main);
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cr_assert_eq(cpu->A, start + main);
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cr_assert_eq(cpu->P & MOS_ZERO, 0);
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cr_assert_eq(cpu->P & MOS_NEGATIVE, 0);
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cr_assert_eq(cpu->P & MOS_OVERFLOW, 0);
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cr_assert_eq(cpu->P & MOS_CARRY, 0);
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// If an add results in Z = 1, it necessarily implies C = 1. Say you
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// have A = 1, and add -1. With two's complement, the binary coded
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// form of -1 is 0xff; thus 0xff + 0x1 = 0x100, or 0x00 after
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// variable overflow, and thus C = 1.
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//
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// NOTE: variable overflow is e.g. when you go from 0xff to 0x00; it
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// means something different from the V/OVERFLOW status in the 6502
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// chip, which cares about going from a positive to a negative, or
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// from a negative to a positive.
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cpu->A = start;
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cpu->P &= ~MOS_CARRY;
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mos6502_handle_adc(cpu, ztest);
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cr_assert_eq(cpu->A, 0);
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cr_assert_eq(cpu->P & MOS_ZERO, MOS_ZERO);
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cr_assert_eq(cpu->P & MOS_NEGATIVE, 0);
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cr_assert_eq(cpu->P & MOS_OVERFLOW, 0);
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cr_assert_eq(cpu->P & MOS_CARRY, MOS_CARRY);
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// We can test both negative and overflow here. We could do a
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// separate test on the N flag if we set A = 0x80 and added a small
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// number, like 0x3; we would essentially begin with a negative
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// number and end with a negative number.
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cpu->A = start;
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cpu->P &= ~MOS_CARRY;
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mos6502_handle_adc(cpu, vtest);
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cr_assert_eq(cpu->A, start + vtest);
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cr_assert_eq(cpu->P & MOS_ZERO, 0);
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cr_assert_eq(cpu->P & MOS_NEGATIVE, MOS_NEGATIVE);
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cr_assert_eq(cpu->P & MOS_OVERFLOW, MOS_OVERFLOW);
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cr_assert_eq(cpu->P & MOS_CARRY, 0);
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cpu->A = start;
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cpu->P &= ~MOS_CARRY;
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mos6502_handle_adc(cpu, ctest);
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// Cast to vm_8bit since we're working with variable overflow
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cr_assert_eq(cpu->A, (vm_8bit)(start + ctest));
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cr_assert_eq(cpu->P & MOS_ZERO, 0);
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cr_assert_eq(cpu->P & MOS_NEGATIVE, 0);
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cr_assert_eq(cpu->P & MOS_OVERFLOW, 0);
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cr_assert_eq(cpu->P & MOS_CARRY, MOS_CARRY);
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// This should handle decimal mode without complaint
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cpu->P |= MOS_DECIMAL;
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cpu->P &= ~MOS_CARRY;
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cpu->A = 0x18;
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mos6502_handle_adc(cpu, 0x3);
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cr_assert_eq(cpu->A, 0x21);
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@ -270,8 +332,6 @@ Test(mos6502_arith, inx)
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ntest = 0x7F,
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ztest = 0xFF;
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vm_16bit addr = 0x123;
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cpu->addr_mode = ACC;
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mos6502_handle_inx(cpu, main);
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cr_assert_eq(cpu->X, main + 1);
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@ -297,8 +357,6 @@ Test(mos6502_arith, iny)
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ntest = 0x7F,
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ztest = 0xFF;
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vm_16bit addr = 0x123;
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cpu->addr_mode = ACC;
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mos6502_handle_iny(cpu, main);
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cr_assert_eq(cpu->Y, main + 1);
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