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Add some debugging output
Fix InstCombine/2004-03-13-InstCombineInfLoop.ll which caused an infinite loop compiling (I think) povray. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@12365 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -33,6 +33,7 @@
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//
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//===----------------------------------------------------------------------===//
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#define DEBUG_TYPE "instcombine"
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#include "llvm/Transforms/Scalar.h"
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#include "llvm/Instructions.h"
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#include "llvm/Intrinsics.h"
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@ -46,6 +47,7 @@
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#include "llvm/Support/InstIterator.h"
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#include "llvm/Support/InstVisitor.h"
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#include "llvm/Support/CallSite.h"
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#include "Support/Debug.h"
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#include "Support/Statistic.h"
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#include <algorithm>
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using namespace llvm;
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@ -1551,7 +1553,7 @@ Instruction *InstCombiner::visitSetCondInst(BinaryOperator &I) {
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if (CastInst *CI = dyn_cast<CastInst>(Op0)) {
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Value *CastOp0 = CI->getOperand(0);
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if (CastOp0->getType()->isLosslesslyConvertibleTo(CI->getType()) &&
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!isa<Argument>(Op1) &&
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(isa<Constant>(Op1) || isa<CastInst>(Op1)) &&
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(I.getOpcode() == Instruction::SetEQ ||
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I.getOpcode() == Instruction::SetNE)) {
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// We keep moving the cast from the left operand over to the right
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@ -2543,6 +2545,9 @@ bool InstCombiner::runOnFunction(Function &F) {
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++NumCombined;
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// Should we replace the old instruction with a new one?
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if (Result != I) {
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DEBUG(std::cerr << "IC: Old = " << *I
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<< " New = " << *Result);
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// Instructions can end up on the worklist more than once. Make sure
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// we do not process an instruction that has been deleted.
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removeFromWorkList(I);
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@ -2561,6 +2566,8 @@ bool InstCombiner::runOnFunction(Function &F) {
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// Erase the old instruction.
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InstParent->getInstList().erase(I);
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} else {
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DEBUG(std::cerr << "IC: MOD = " << *I);
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BasicBlock::iterator II = I;
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// If the instruction was modified, it's possible that it is now dead.
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