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Make use of the exact bit when optimizing '(X >>exact 3) << 1' to eliminate the
'and' that would zero out the trailing bits, and to produce an exact shift ourselves. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@147391 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -536,12 +536,11 @@ Instruction *InstCombiner::FoldShiftByConstant(Value *Op0, ConstantInt *Op1,
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if (ShiftAmt1 == 0) return 0; // Will be simplified in the future.
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Value *X = ShiftOp->getOperand(0);
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uint32_t AmtSum = ShiftAmt1+ShiftAmt2; // Fold into one big shift.
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IntegerType *Ty = cast<IntegerType>(I.getType());
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// Check for (X << c1) << c2 and (X >> c1) >> c2
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if (I.getOpcode() == ShiftOp->getOpcode()) {
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uint32_t AmtSum = ShiftAmt1+ShiftAmt2; // Fold into one big shift.
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// If this is oversized composite shift, then unsigned shifts get 0, ashr
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// saturates.
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if (AmtSum >= TypeBits) {
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@ -603,9 +602,16 @@ Instruction *InstCombiner::FoldShiftByConstant(Value *Op0, ConstantInt *Op1,
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// (X >>? C1) << C2 --> X >>? (C1-C2) & (-1 << C2)
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if (I.getOpcode() == Instruction::Shl &&
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ShiftOp->getOpcode() != Instruction::Shl) {
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Value *Shift = Builder->CreateBinOp(ShiftOp->getOpcode(), X,
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ConstantInt::get(Ty, ShiftDiff));
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ConstantInt *ShiftDiffCst = ConstantInt::get(Ty, ShiftDiff);
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if (ShiftOp->isExact()) {
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// (X >>?exact C1) << C2 --> X >>?exact (C1-C2)
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BinaryOperator *NewShr = BinaryOperator::Create(ShiftOp->getOpcode(),
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X, ShiftDiffCst);
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NewShr->setIsExact(true);
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return NewShr;
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}
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Value *Shift = Builder->CreateBinOp(ShiftOp->getOpcode(),
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X, ShiftDiffCst);
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APInt Mask(APInt::getHighBitsSet(TypeBits, TypeBits - ShiftAmt2));
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return BinaryOperator::CreateAnd(Shift,
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ConstantInt::get(I.getContext(),Mask));
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