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Fast-track obviously over-large and over-small exponents during decimal->
integer conversion. In some such cases this makes us one or two orders of magnitude faster than NetBSD's libc. Glibc seems to have a similar fast path. Also, tighten up some upper bounds to save a bit of memory. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@42984 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -59,7 +59,7 @@ namespace llvm {
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/* A tight upper bound on number of parts required to hold the value
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pow(5, power) is
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power * 1024 / (441 * integerPartWidth) + 1
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power * 815 / (351 * integerPartWidth) + 1
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However, whilst the result may require only this many parts,
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because we are multiplying two values to get it, the
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@ -70,8 +70,8 @@ namespace llvm {
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const unsigned int maxExponent = 16383;
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const unsigned int maxPrecision = 113;
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const unsigned int maxPowerOfFiveExponent = maxExponent + maxPrecision - 1;
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const unsigned int maxPowerOfFiveParts = 2 + ((maxPowerOfFiveExponent * 1024)
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/ (441 * integerPartWidth));
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const unsigned int maxPowerOfFiveParts = 2 + ((maxPowerOfFiveExponent * 815)
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/ (351 * integerPartWidth));
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}
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/* Put a bunch of private, handy routines in an anonymous namespace. */
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@ -226,12 +226,19 @@ namespace {
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dddd.dddd[eE][+-]ddd
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where the decimal point and exponent are optional, fill out the
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structure D. If the value is zero, V->firstSigDigit
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points to a zero, and the return exponent is zero. */
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structure D. Exponent is appropriate if the significand is
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treated as an integer, and normalizedExponent if the significand
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is taken to have the decimal point after a single leading
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non-zero digit.
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If the value is zero, V->firstSigDigit points to a zero, and the
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return exponent is zero.
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*/
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struct decimalInfo {
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const char *firstSigDigit;
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const char *lastSigDigit;
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int exponent;
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int normalizedExponent;
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};
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void
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@ -243,6 +250,7 @@ namespace {
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D->firstSigDigit = p;
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D->exponent = 0;
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D->normalizedExponent = 0;
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for (;;) {
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if (*p == '.') {
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@ -270,8 +278,10 @@ namespace {
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while (*p == '0');
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while (*p == '.');
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/* Adjust the specified exponent for any decimal point. */
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/* Adjust the exponents for any decimal point. */
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D->exponent += (dot - p) - (dot > p);
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D->normalizedExponent = (D->exponent + (p - D->firstSigDigit)
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- (dot > D->firstSigDigit && dot < p));
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}
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D->lastSigDigit = p;
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@ -2079,19 +2089,45 @@ APFloat::convertFromDecimalString(const char *p, roundingMode rounding_mode)
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/* Scan the text. */
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interpretDecimal(p, &D);
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/* Handle the quick cases. First the case of no significant digits,
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i.e. zero, and then exponents that are obviously too large or too
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small. Writing L for log 10 / log 2, a number d.ddddd*10^exp
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definitely overflows if
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(exp - 1) * L >= maxExponent
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and definitely underflows to zero where
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(exp + 1) * L <= minExponent - precision
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With integer arithmetic the tightest bounds for L are
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93/28 < L < 196/59 [ numerator <= 256 ]
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42039/12655 < L < 28738/8651 [ numerator <= 65536 ]
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*/
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if (*D.firstSigDigit == '0') {
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category = fcZero;
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fs = opOK;
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} else if ((D.normalizedExponent + 1) * 28738
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<= 8651 * (semantics->minExponent - (int) semantics->precision)) {
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/* Underflow to zero and round. */
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zeroSignificand();
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fs = normalize(rounding_mode, lfLessThanHalf);
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} else if ((D.normalizedExponent - 1) * 42039
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>= 12655 * semantics->maxExponent) {
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/* Overflow and round. */
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fs = handleOverflow(rounding_mode);
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} else {
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integerPart *decSignificand;
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unsigned int partCount;
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/* A tight upper bound on number of bits required to hold an
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N-digit decimal integer is N * 256 / 77. Allocate enough space
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N-digit decimal integer is N * 196 / 59. Allocate enough space
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to hold the full significand, and an extra part required by
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tcMultiplyPart. */
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partCount = (D.lastSigDigit - D.firstSigDigit) + 1;
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partCount = partCountForBits(1 + 256 * partCount / 77);
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partCount = partCountForBits(1 + 196 * partCount / 59);
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decSignificand = new integerPart[partCount + 1];
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partCount = 0;
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