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slightly simplify code and substantially improve comment. Instead of

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saying "it would be bad", give an example of what is going on.


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@119695 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Chris Lattner 2010-11-18 08:07:09 +00:00
parent 5a7aeaa019
commit d528be6636
1 changed files with 23 additions and 20 deletions
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43
lib/Transforms/Scalar/MemCpyOptimizer.cpp
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@ -712,34 +712,37 @@ bool MemCpyOpt::processMemCpyMemCpyDependence(MemCpyInst *M, MemCpyInst *MDep,
// the alignment past what can be read from or written to.
// TODO: Is this worth it if we're creating a less aligned memcpy? For
// example we could be moving from movaps -> movq on x86.
unsigned Align = std::min(MDep->getAlignmentCst()->getZExtValue(),
M->getAlignmentCst()->getZExtValue());
LLVMContext &Context = M->getContext();
ConstantInt *AlignCI = ConstantInt::get(Type::getInt32Ty(Context), Align);
unsigned Align = std::min(MDep->getAlignment(), M->getAlignment());
Value *Args[5] = {
M->getRawDest(), MDep->getRawSource(), M->getLength(),
AlignCI, M->getVolatileCst()
M->getRawDest(),
MDep->getRawSource(),
M->getLength(),
ConstantInt::get(Type::getInt32Ty(M->getContext()), Align),
M->getVolatileCst()
};
CallInst *C = CallInst::Create(MemCpyFun, Args, Args+5, "", M);
MemoryDependenceAnalysis &MD = getAnalysis<MemoryDependenceAnalysis>();
// If C and M don't interfere, then this is a valid transformation. If they
// did, this would mean that the two sources overlap, which would be bad.
MemDepResult dep = MD.getDependency(C);
if (dep.isClobber() && dep.getInst() == MDep) {
MD.removeInstruction(M);
M->eraseFromParent();
++NumMemCpyInstr;
return true;
// Verify that the copied-from memory doesn't change in between the two
// transfers. For example, in:
// memcpy(a <- b)
// *b = 42;
// memcpy(c <- a)
// It would be invalid to transform the second memcpy into memcpy(c <- b).
MemDepResult NewDep = MD.getDependency(C);
if (!NewDep.isClobber() || NewDep.getInst() != MDep) {
MD.removeInstruction(C);
C->eraseFromParent();
return false;
}
// Otherwise, there was no point in doing this, so we remove the call we
// inserted and act like nothing happened.
MD.removeInstruction(C);
C->eraseFromParent();
return false;
// Otherwise we're good! Nuke the instruction we're replacing.
MD.removeInstruction(M);
M->eraseFromParent();
++NumMemCpyInstr;
return true;
}