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My super-optimizer noticed that we weren't folding this expression to
true: (x *nsw x) sgt 0, where x = (y | 1). This occurs in 464.h264ref. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@143028 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -201,9 +201,36 @@ void llvm::ComputeMaskedBits(Value *V, const APInt &Mask,
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ComputeMaskedBits(I->getOperand(1), Mask2, KnownZero, KnownOne, TD,Depth+1);
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ComputeMaskedBits(I->getOperand(0), Mask2, KnownZero2, KnownOne2, TD,
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Depth+1);
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assert((KnownZero & KnownOne) == 0 && "Bits known to be one AND zero?");
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assert((KnownZero2 & KnownOne2) == 0 && "Bits known to be one AND zero?");
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assert((KnownZero & KnownOne) == 0 && "Bits known to be one AND zero?");
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assert((KnownZero2 & KnownOne2) == 0 && "Bits known to be one AND zero?");
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bool isKnownNegative = false;
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bool isKnownNonNegative = false;
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// If the multiplication is known not to overflow, compute the sign bit.
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if (Mask.isNegative() && cast<BinaryOperator>(I)->hasNoSignedWrap()) {
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Value *Op1 = I->getOperand(1), *Op2 = I->getOperand(0);
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if (Op1 == Op2) {
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// The product of a number with itself is non-negative.
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isKnownNonNegative = true;
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} else {
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bool isKnownNonNegative1 = KnownZero.isNegative();
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bool isKnownNonNegative2 = KnownZero2.isNegative();
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bool isKnownNegative1 = KnownOne.isNegative();
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bool isKnownNegative2 = KnownOne2.isNegative();
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// The product of two numbers with the same sign is non-negative.
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isKnownNonNegative = (isKnownNegative1 && isKnownNegative2) ||
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(isKnownNonNegative1 && isKnownNonNegative2);
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// The product of a negative number and a non-negative number is either
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// negative or zero.
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isKnownNegative = (isKnownNegative1 && isKnownNonNegative2 &&
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isKnownNonZero(Op2, TD, Depth)) ||
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(isKnownNegative2 && isKnownNonNegative1 &&
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isKnownNonZero(Op1, TD, Depth));
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assert(!(isKnownNegative && isKnownNonNegative) &&
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"Sign bit both zero and one?");
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}
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}
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// If low bits are zero in either operand, output low known-0 bits.
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// Also compute a conserative estimate for high known-0 bits.
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// More trickiness is possible, but this is sufficient for the
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@ -220,6 +247,12 @@ void llvm::ComputeMaskedBits(Value *V, const APInt &Mask,
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KnownZero = APInt::getLowBitsSet(BitWidth, TrailZ) |
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APInt::getHighBitsSet(BitWidth, LeadZ);
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KnownZero &= Mask;
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if (isKnownNonNegative)
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KnownZero.setBit(BitWidth - 1);
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else if (isKnownNegative)
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KnownOne.setBit(BitWidth - 1);
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return;
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}
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case Instruction::UDiv: {
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@ -767,7 +800,7 @@ bool llvm::isKnownNonZero(Value *V, const TargetData *TD, unsigned Depth) {
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}
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// The remaining tests are all recursive, so bail out if we hit the limit.
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if (Depth++ == MaxDepth)
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if (Depth++ >= MaxDepth)
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return false;
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unsigned BitWidth = getBitWidth(V->getType(), TD);
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@ -851,6 +884,15 @@ bool llvm::isKnownNonZero(Value *V, const TargetData *TD, unsigned Depth) {
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if (YKnownNonNegative && isPowerOfTwo(X, TD, Depth))
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return true;
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}
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// X * Y.
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else if (match(V, m_Mul(m_Value(X), m_Value(Y)))) {
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BinaryOperator *BO = cast<BinaryOperator>(V);
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// If X and Y are non-zero then so is X * Y as long as the multiplication
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// does not overflow.
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if ((BO->hasNoSignedWrap() || BO->hasNoUnsignedWrap()) &&
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isKnownNonZero(X, TD, Depth) && isKnownNonZero(Y, TD, Depth))
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return true;
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}
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// (C ? X : Y) != 0 if X != 0 and Y != 0.
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else if (SelectInst *SI = dyn_cast<SelectInst>(V)) {
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if (isKnownNonZero(SI->getTrueValue(), TD, Depth) &&
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@ -323,3 +323,34 @@ define i1 @and1(i32 %X) {
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ret i1 %B
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; CHECK: ret i1 false
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}
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define i1 @mul1(i32 %X) {
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; CHECK: @mul1
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; Square of a non-zero number is non-zero if there is no overflow.
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%Y = or i32 %X, 1
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%M = mul nuw i32 %Y, %Y
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%C = icmp eq i32 %M, 0
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ret i1 %C
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; CHECK: ret i1 false
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}
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define i1 @mul2(i32 %X) {
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; CHECK: @mul2
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; Square of a non-zero number is positive if there is no signed overflow.
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%Y = or i32 %X, 1
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%M = mul nsw i32 %Y, %Y
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%C = icmp sgt i32 %M, 0
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ret i1 %C
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; CHECK: ret i1 true
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}
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define i1 @mul3(i32 %X, i32 %Y) {
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; CHECK: @mul3
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; Product of non-negative numbers is non-negative if there is no signed overflow.
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%XX = mul nsw i32 %X, %X
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%YY = mul nsw i32 %Y, %Y
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%M = mul nsw i32 %XX, %YY
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%C = icmp sge i32 %M, 0
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ret i1 %C
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; CHECK: ret i1 true
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}
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