LSR should avoid redundant edge splitting.

This handles the case in which LSR rewrites an IV user that is a phi and
splits critical edges originating from a switch.
Fixes <rdar://problem/6453893> LSR is not splitting edges "nicely"


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@141059 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Andrew Trick
2011-10-04 03:50:44 +00:00
parent 2aeb8027d6
commit f143b79b78
4 changed files with 55 additions and 6 deletions

View File

@ -109,7 +109,8 @@ bool isCriticalEdge(const TerminatorInst *TI, unsigned SuccNum,
/// to.
///
BasicBlock *SplitCriticalEdge(TerminatorInst *TI, unsigned SuccNum,
Pass *P = 0, bool MergeIdenticalEdges = false);
Pass *P = 0, bool MergeIdenticalEdges = false,
bool DontDeleteUselessPHIs = false);
inline BasicBlock *SplitCriticalEdge(BasicBlock *BB, succ_iterator SI,
Pass *P = 0) {
@ -136,13 +137,15 @@ inline bool SplitCriticalEdge(BasicBlock *Succ, pred_iterator PI, Pass *P = 0) {
/// described above.
inline BasicBlock *SplitCriticalEdge(BasicBlock *Src, BasicBlock *Dst,
Pass *P = 0,
bool MergeIdenticalEdges = false) {
bool MergeIdenticalEdges = false,
bool DontDeleteUselessPHIs = false) {
TerminatorInst *TI = Src->getTerminator();
unsigned i = 0;
while (1) {
assert(i != TI->getNumSuccessors() && "Edge doesn't exist!");
if (TI->getSuccessor(i) == Dst)
return SplitCriticalEdge(TI, i, P, MergeIdenticalEdges);
return SplitCriticalEdge(TI, i, P, MergeIdenticalEdges,
DontDeleteUselessPHIs);
++i;
}
}