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	The failures in r116753 r116756 were caused by a python issue - Python likes to append 'L' suffix to stringified numbers if the number is larger than a machine int. Unfortunately, this causes a divergence of behavior between 32 and 64 bit python versions. I re-crafted elf-dump/common_dump to take care of these issues by: 1. always printing 0x (makes for easy sed/regex) 2. always print fixed length (exactly 2 + numBits/4 digits long) by mod ((2^numBits) - 1) 3. left-padded with '0' There is a residual common routine that is also used by macho-dump (dataToHex) , so I left the 'section_data' test values alone. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@116823 91177308-0d34-0410-b5e6-96231b3b80d8
		
			
				
	
	
		
			47 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			47 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
def dataToHex(d):
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    """ Convert the raw data in 'd' to an hex string with a space every 4 bytes.
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    """
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    bytes = []
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    for i,c in enumerate(d):
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        byte = ord(c)
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        hex_byte = hex(byte)[2:]
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        if byte <= 0xf:
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            hex_byte = '0' + hex_byte
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        if i % 4 == 3:
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            hex_byte += ' '
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        bytes.append(hex_byte)
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    return ''.join(bytes).strip()
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def dataToHexUnified(d):
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    """ Convert the raw data in 'd' to an hex string with a space every 4 bytes.
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    Each 4byte number is prefixed with 0x for easy sed/rx
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    Fixme: convert all MC tests to use this routine instead of the above
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    """
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    bytes = []
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    for i,c in enumerate(d):
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        byte = ord(c)
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        hex_byte = hex(byte)[2:]
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        if byte <= 0xf:
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            hex_byte = '0' + hex_byte
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        if i % 4 == 0:
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            hex_byte = '0x' + hex_byte
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        if i % 4 == 3:
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            hex_byte += ' '
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        bytes.append(hex_byte)
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    return ''.join(bytes).strip()
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def HexDump(val, numBits=32):
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    """
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    1. do not print 'L'
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    2. Handle negatives and large numbers by mod (2^numBits)
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    3. print fixed length, prepend with zeros.
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       Length is exactly 2+(numBits/4)
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    4. Do print 0x Why?
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       so that they can be easily distinguished using sed/rx
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    """
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    val = val & (( 1 << numBits) - 1)
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    newFmt = "0x%0" + "%d" % (numBits / 4) + "x"
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    return newFmt % val
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