ORCA-C/Tests/Conformance/C15.7.0.2.CC
Stephen Heumann 91d33b586d Fix various C99+ conformance issues and bugs in test cases.
The main changes made to most tests are:

*Declarations always include explicit types, not relying on implicit int. The declaration of main in most test programs is changed to be "int main (void) {...}", adding an explicit return type and a prototype. (There are still some non-prototyped functions, though.)

*Functions are always declared before use, either by including a header or by providing a declaration for the specific function. The latter approach is usually used for printf, to avoid requiring ORCA/C to process stdio.h when compiling every test case (which might make test runs noticeably slower).

*Make all return statements in non-void functions (e.g. main) return a value.

*Avoid some instances of undefined behavior and type errors in printf and scanf calls.

Several miscellaneous bugs are also fixed.

There are still a couple test cases that intentionally rely on the C89 behavior, to ensure it still works.
2022-10-17 20:17:24 -05:00

109 lines
2.5 KiB
C++

/* Conformance Test 15.7.0.2: Verification of strtok function */
#include <stddef.h>
#include <string.h>
int printf(const char *, ...);
int main (void)
{
char string [] = " this is the source string, so creative! oh, yes";
char *strPtr;
/* First call to strtok pass the string to be parsed; subsequent calls */
/* just pass a NULL pointer. Separating character is space to start. */
strPtr = strtok (string, " ");
if (strPtr != (&( (string) [(1)] )) )
goto Fail;
strPtr = strtok (NULL, " ");
if (strPtr != &string [6])
goto Fail;
strPtr = strtok (NULL, " ");
if (strPtr != &string [9])
goto Fail;
strPtr = strtok (NULL, " ");
if (strPtr != &string [13])
goto Fail;
strPtr = strtok (NULL, ","); /* now change the separator set */
if (strPtr != &string [20])
goto Fail;
strPtr = strtok (NULL, ",");
if (strPtr != &string [27])
goto Fail;
strPtr = strtok (NULL, "! &*"); /* make last calls to strtok */
if (strPtr != &string [45]) /* address of '\0' at end of string */
goto Fail;
strPtr = strtok (NULL, " ");
if (strPtr != NULL)
goto Fail;
/* Check tokenized string created by successive calls to strtok. */
strcpy(string, " this is the source string, so creative! oh, yes");
strPtr = strtok (string, " ");
if (strcmp (strPtr, "this"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "is"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "the"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "source"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "string,"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "so"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "creative!"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "oh,"))
goto Fail;
strPtr = strtok (NULL, " ");
if (strcmp (strPtr, "yes"))
goto Fail;
/* Check "special" cases: string is the null string, and the string */
/* contains only separator characters */
strPtr = strtok ("", " ");
if (strPtr != NULL)
goto Fail;
strPtr = strtok ("abc", "abc");
if (strPtr != NULL)
goto Fail;
printf ("Passed Conformance Test 15.7.0.2\n");
return 0;
Fail:
printf ("Failed Conformance Test 15.7.0.2\n");
}