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Modified print_subst_w_backrefs() so it will print backslash escaped
characters properly, just like GNU sed.
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@ -500,6 +500,12 @@ static void print_subst_w_backrefs(const char *line, const char *replace, regmat
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fputc(line[j], stdout);
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}
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/* if we find a backslash escaped character, print the character */
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else if (replace[i] == '\\') {
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++i;
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fputc(replace[i], stdout);
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}
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/* if we find an unescaped '&' print out the whole matched text.
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* fortunately, regmatch[0] contains the indicies to the whole matched
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* expression (kinda seems like it was designed for just such a
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6
sed.c
6
sed.c
@ -500,6 +500,12 @@ static void print_subst_w_backrefs(const char *line, const char *replace, regmat
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fputc(line[j], stdout);
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}
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/* if we find a backslash escaped character, print the character */
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else if (replace[i] == '\\') {
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++i;
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fputc(replace[i], stdout);
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}
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/* if we find an unescaped '&' print out the whole matched text.
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* fortunately, regmatch[0] contains the indicies to the whole matched
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* expression (kinda seems like it was designed for just such a
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