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libbb: make "COMMON_BUFSIZE = 1024 bytes, the buffer will be malloced" work
Signed-off-by: Denys Vlasenko <vda.linux@googlemail.com>
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df70a43af2
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@ -55,14 +55,14 @@ char bb_common_bufsiz1[COMMON_BUFSIZE] ALIGNED(sizeof(long long));
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# ifndef setup_common_bufsiz
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/*
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* It is not a "((void)0)" macro. It means we have to provide this function.
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* It is not defined as a dummy macro.
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* It means we have to provide this function.
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*/
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char* bb_common_bufsiz1;
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char* setup_common_bufsiz(void)
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void setup_common_bufsiz(void)
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{
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if (!bb_common_bufsiz1)
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bb_common_bufsiz1 = xzalloc(COMMON_BUFSIZE);
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return bb_common_bufsiz1;
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}
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# else
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# ifndef bb_common_bufsiz1
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@ -87,7 +87,8 @@ if test $REM -lt 1024; then
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echo "Rerun make to build a binary which doesn't use it!"
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exit 1
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fi
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exit 0
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echo "COMMON_BUFSIZE = 1024 bytes, the buffer will be malloced"
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exit 0
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fi
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# _end[] has REM bytes for bb_common_bufsiz1[]
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@ -102,7 +103,7 @@ echo "#define setup_common_bufsiz() ((void)0)"
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} | regenerate "$common_bufsiz_h"
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echo $REM >"$common_bufsiz_h.BUFSIZE"
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# Check that code did not grow too much and thus _end[] did not shink:
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# Check that code did not grow too much and thus _end[] did not shrink:
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if test $OLD -gt $REM; then
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echo "Warning! Space in _end[] has decreased from $OLD to $REM bytes!"
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echo "Rerun make!"
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