Retro68/binutils/libiberty/spaces.c
2017-10-07 02:16:47 +02:00

70 lines
1.8 KiB
C

/* Allocate memory region filled with spaces.
Copyright (C) 1991-2017 Free Software Foundation, Inc.
This file is part of the libiberty library.
Libiberty is free software; you can redistribute it and/or
modify it under the terms of the GNU Library General Public
License as published by the Free Software Foundation; either
version 2 of the License, or (at your option) any later version.
Libiberty is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Library General Public License for more details.
You should have received a copy of the GNU Library General Public
License along with libiberty; see the file COPYING.LIB. If
not, write to the Free Software Foundation, Inc., 51 Franklin Street - Fifth Floor,
Boston, MA 02110-1301, USA. */
/*
@deftypefn Extension char* spaces (int @var{count})
Returns a pointer to a memory region filled with the specified
number of spaces and null terminated. The returned pointer is
valid until at least the next call.
@end deftypefn
*/
#ifdef HAVE_CONFIG_H
#include "config.h"
#endif
#include "ansidecl.h"
#include "libiberty.h"
#if VMS
#include <stdlib.h>
#include <unixlib.h>
#else
/* For systems with larger pointers than ints, these must be declared. */
extern PTR malloc (size_t);
extern void free (PTR);
#endif
const char *
spaces (int count)
{
register char *t;
static char *buf;
static int maxsize;
if (count > maxsize)
{
free (buf);
buf = (char *) malloc (count + 1);
if (buf == (char *) 0)
return 0;
for (t = buf + count ; t != buf ; )
{
*--t = ' ';
}
maxsize = count;
buf[count] = '\0';
}
return (const char *) (buf + maxsize - count);
}