From 34e5f3957151d62de22d0d264ec8a6a5d5800acc Mon Sep 17 00:00:00 2001
From: Thomas Harte <thomas.harte@gmail.com>
Date: Mon, 23 May 2022 15:11:33 -0400
Subject: [PATCH] Ensure that running exactly up to a boundary gives the bus
 handler the next microcycle to contemplate.

---
 Processors/68000Mk2/Implementation/68000Mk2Implementation.hpp | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/Processors/68000Mk2/Implementation/68000Mk2Implementation.hpp b/Processors/68000Mk2/Implementation/68000Mk2Implementation.hpp
index 53e84857e..1c1cfa83a 100644
--- a/Processors/68000Mk2/Implementation/68000Mk2Implementation.hpp
+++ b/Processors/68000Mk2/Implementation/68000Mk2Implementation.hpp
@@ -189,11 +189,11 @@ template <class BusHandler, bool dtack_is_implicit, bool permit_overrun, bool si
 void Processor<BusHandler, dtack_is_implicit, permit_overrun, signal_will_perform>::run_for(HalfCycles duration) {
 	// Accumulate the newly paid-in cycles. If this instance remains in deficit, exit.
 	time_remaining_ += duration;
-	if(time_remaining_ <= HalfCycles(0)) return;
+	if(time_remaining_ < HalfCycles(0)) return;
 
 	// Check whether all remaining time has been expended; if so then exit, having set this line up as
 	// the next resumption point.
-#define ConsiderExit()	if(time_remaining_ <= HalfCycles(0)) { state_ = __COUNTER__+1; return; } [[fallthrough]]; case __COUNTER__:
+#define ConsiderExit()	if(time_remaining_ < HalfCycles(0)) { state_ = __COUNTER__+1; return; } [[fallthrough]]; case __COUNTER__:
 
 	// Subtracts `n` half-cycles from `time_remaining_`; if permit_overrun is false, also ConsiderExit()
 #define Spend(n)		time_remaining_ -= (n); if constexpr (!permit_overrun) ConsiderExit()