mirror of
https://github.com/TomHarte/CLK.git
synced 2024-11-26 23:52:26 +00:00
Build max
into the sequencer.
This commit is contained in:
parent
05d2e78f80
commit
77c67ab59d
@ -11,7 +11,7 @@
|
||||
|
||||
namespace Dispatcher {
|
||||
|
||||
template <int max, typename SequencerT>
|
||||
template <typename SequencerT>
|
||||
struct Dispatcher {
|
||||
|
||||
/// Perform @c target.perform<n>() for the input range `start <= n < end`.
|
||||
@ -21,7 +21,7 @@ struct Dispatcher {
|
||||
// Minor optimisation: do a comparison with end once outside the loop and if it implies so
|
||||
// then do no further comparisons within the loop. This is somewhat targetted at expected
|
||||
// use cases.
|
||||
if(end < max) {
|
||||
if(end < SequencerT::max) {
|
||||
dispatch<true>(target, start, end, args...);
|
||||
} else {
|
||||
dispatch<false>(target, start, end, args...);
|
||||
@ -30,7 +30,7 @@ struct Dispatcher {
|
||||
|
||||
private:
|
||||
template <bool use_end, typename... Args> void dispatch(SequencerT &target, int start, int end, Args&&... args) {
|
||||
static_assert(max < 2048);
|
||||
static_assert(SequencerT::max < 2048);
|
||||
|
||||
// Yes, macros, yuck. But I want an actual switch statement for the dispatch to start
|
||||
// and to allow a simple [[fallthrough]] through all subsequent steps up until end.
|
||||
@ -38,15 +38,15 @@ private:
|
||||
//
|
||||
// Sensible choices by the optimiser are assumed.
|
||||
|
||||
#define index(n) \
|
||||
case n: \
|
||||
if constexpr (n <= max) { \
|
||||
if constexpr (n == max) return; \
|
||||
if constexpr (n < max) { \
|
||||
if(use_end && end == n) return; \
|
||||
} \
|
||||
target.template perform<n>(args...); \
|
||||
} \
|
||||
#define index(n) \
|
||||
case n: \
|
||||
if constexpr (n <= SequencerT::max) { \
|
||||
if constexpr (n == SequencerT::max) return; \
|
||||
if constexpr (n < SequencerT::max) { \
|
||||
if(use_end && end == n) return; \
|
||||
} \
|
||||
target.template perform<n>(args...); \
|
||||
} \
|
||||
[[fallthrough]];
|
||||
|
||||
#define index2(n) index(n); index(n+1);
|
||||
|
Loading…
Reference in New Issue
Block a user