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README.md
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README.md
@ -83,6 +83,8 @@ The problem is that once a byte is extracted, putting it back into a word is awk
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The address operators have to modify a destination in a special way. That is, when
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you say `st a, >word`, you are updating `word` to be `word & $ff | a << 8`, somelike.
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Is that consistent with `st`? Well, probably it is, but we have to explain it.
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It might make more sense, then, for it to be "part of the operation" instead of "part of
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the reference"; something like `st.hi x, word`; `st.lo y, word`. Dunno.
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### Save registers on stack
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@ -91,9 +93,17 @@ are trashed inside the block.
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### Associate each pointer with the buffer it points into
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Check that the buffer being read or written to through pointer, appears in appropriate inputs or outputs set.
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Check that the buffer being read or written to through pointer, appears in appropriate
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inputs or outputs set.
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### `static` tables
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In the analysis, when we obtain a pointer, we need to record, in contect, what buffer
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that pointer came from.
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When we write through that pointer, we need to set that buffer as written.
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When we read through the pointer, we need to check that the buffer is readable.
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### table overlays
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They are uninitialized, but the twist is, the address is a buffer that is
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an input to and/or output of the routine. So, they are defined (insofar
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@ -104,8 +114,14 @@ They are therefore a "view" of a section of a buffer.
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This is slightly dangerous since it does permit aliases: the buffer and the
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table refer to the same memory.
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`static` tables overlayed on buffers is an alternative to `static` pointers
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(which are currently not possible because pointers must be zero-page, thus `@`, thus uninitialized.)
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Although, if they are `static`, you could say, in the routine in which they
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are `static`, as soon as you've established one, you can no longer use the
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buffer; and the ones you establish must be disjoint.
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(That seems to be the most compelling case for restricting them to `static`.)
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An alternative would be `static` pointers, which are currently not possible because
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pointers must be zero-page, thus `@`, thus uninitialized.
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### Question "consistent initialization"
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