2002-05-02 20:41:39 +00:00
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; This is the test case taken from appel's book that illustrates a hard case
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; that SCCP gets right. BB3 should be completely eliminated.
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;
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2003-09-16 15:29:54 +00:00
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; RUN: llvm-as < %s | opt -sccp -constprop -dce -cfgsimplify | llvm-dis | not grep BB3
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2002-05-02 20:41:39 +00:00
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2003-06-28 23:23:34 +00:00
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int %test function(int %i0, int %j0) {
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2002-05-02 20:41:39 +00:00
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BB1:
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br label %BB2
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BB2:
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%j2 = phi int [%j4, %BB7], [1, %BB1]
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%k2 = phi int [%k4, %BB7], [0, %BB1]
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%kcond = setlt int %k2, 100
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br bool %kcond, label %BB3, label %BB4
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BB3:
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%jcond = setlt int %j2, 20
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br bool %jcond, label %BB5, label %BB6
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BB4:
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ret int %j2
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BB5:
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%k3 = add int %k2, 1
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br label %BB7
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BB6:
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%k5 = add int %k2, 1
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br label %BB7
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BB7:
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%j4 = phi int [1, %BB5], [%k2, %BB6]
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%k4 = phi int [%k3, %BB5], [%k5, %BB6]
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br label %BB2
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2003-06-28 23:23:34 +00:00
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}
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