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When determining whether the new instruction was already present in
the original instruction, half the cases were missed (making it not wrong but suboptimal). Also correct a typo (A <-> B) in the second chunk. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@122414 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -159,10 +159,11 @@ static Value *FactorizeBinOp(unsigned Opcode, Value *LHS, Value *RHS,
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// Does "B op DD" simplify?
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if (Value *V = SimplifyBinOp(Opcode, B, DD, TD, DT, MaxRecurse)) {
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// It does! Return "A op' V" if it simplifies or is already available.
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// If V equals B then "A op' V" is just the LHS.
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if (V == B) {
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// If V equals B then "A op' V" is just the LHS. If V equals DD then
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// "A op' V" is just the RHS.
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if (V == B || V == DD) {
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++NumFactor;
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return LHS;
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return V == B ? LHS : RHS;
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}
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// Otherwise return "A op' V" if it simplifies.
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if (Value *W = SimplifyBinOp(OpcodeToExtract, A, V, TD, DT, MaxRecurse)) {
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@ -181,10 +182,11 @@ static Value *FactorizeBinOp(unsigned Opcode, Value *LHS, Value *RHS,
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// Does "A op CC" simplify?
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if (Value *V = SimplifyBinOp(Opcode, A, CC, TD, DT, MaxRecurse)) {
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// It does! Return "V op' B" if it simplifies or is already available.
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// If V equals A then "V op' B" is just the LHS.
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if (V == B) {
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// If V equals A then "V op' B" is just the LHS. If V equals CC then
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// "V op' B" is just the RHS.
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if (V == A || V == CC) {
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++NumFactor;
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return LHS;
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return V == A ? LHS : RHS;
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}
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// Otherwise return "V op' B" if it simplifies.
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if (Value *W = SimplifyBinOp(OpcodeToExtract, V, B, TD, DT, MaxRecurse)) {
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@ -20,6 +20,17 @@ define i32 @factorize2(i32 %x) {
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; CHECK: ret i32 %x
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}
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define i32 @factorize3(i32 %x, i32 %a, i32 %b) {
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; CHECK: @factorize3
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; (X | (A|B)) & (X | B) -> X | ((A|B) & B) -> X | B
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%aORb = or i32 %a, %b
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%l = or i32 %x, %aORb
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%r = or i32 %x, %b
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%z = and i32 %l, %r
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ret i32 %z
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; CHECK: ret i32 %r
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}
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define i32 @expand(i32 %x) {
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; CHECK: @expand
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; ((X & 1) | 2) & 1 -> ((X & 1) & 1) | (2 & 1) -> (X & 1) | 0 -> X & 1
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