diff --git a/tools/llvm-upgrade/UpgradeParser.y b/tools/llvm-upgrade/UpgradeParser.y index 30d72711153..cec366df592 100644 --- a/tools/llvm-upgrade/UpgradeParser.y +++ b/tools/llvm-upgrade/UpgradeParser.y @@ -570,6 +570,7 @@ static void ResolveTypeTo(char *Name, const Type *ToTy) { } } +/// @brief This just makes any name given to it unique, up to MAX_UINT times. static std::string makeNameUnique(const std::string& Name) { static unsigned UniqueNameCounter = 1; std::string Result(Name); @@ -577,6 +578,57 @@ static std::string makeNameUnique(const std::string& Name) { return Result; } +/// This is the implementation portion of TypeHasInteger. It traverses the +/// type given, avoiding recursive types, and returns true as soon as it finds +/// an integer type. If no integer type is found, it returns false. +static bool TypeHasIntegerI(const Type *Ty, std::vector Stack) { + // Handle some easy cases + if (Ty->isPrimitiveType() || (Ty->getTypeID() == Type::OpaqueTyID)) + return false; + if (Ty->isInteger()) + return true; + if (const SequentialType *STy = dyn_cast(Ty)) + return STy->getElementType()->isInteger(); + + // Avoid type structure recursion + for (std::vector::iterator I = Stack.begin(), E = Stack.end(); + I != E; ++I) + if (Ty == *I) + return false; + + // Push us on the type stack + Stack.push_back(Ty); + + if (const FunctionType *FTy = dyn_cast(Ty)) { + if (TypeHasIntegerI(FTy->getReturnType(), Stack)) + return true; + FunctionType::param_iterator I = FTy->param_begin(); + FunctionType::param_iterator E = FTy->param_end(); + for (; I != E; ++I) + if (TypeHasIntegerI(*I, Stack)) + return true; + return false; + } else if (const StructType *STy = dyn_cast(Ty)) { + StructType::element_iterator I = STy->element_begin(); + StructType::element_iterator E = STy->element_end(); + for (; I != E; ++I) { + if (TypeHasIntegerI(*I, Stack)) + return true; + } + return false; + } + // There shouldn't be anything else, but its definitely not integer + assert(0 && "What type is this?"); + return false; +} + +/// This is the interface to TypeHasIntegerI. It just provides the type stack, +/// to avoid recursion, and then calls TypeHasIntegerI. +static inline bool TypeHasInteger(const Type *Ty) { + std::vector TyStack; + return TypeHasIntegerI(Ty, TyStack); +} + // setValueName - Set the specified value to the name given. The name may be // null potentially, in which case this is a noop. The string passed in is // assumed to be a malloc'd string buffer, and is free'd by this function. @@ -605,16 +657,16 @@ static void setValueName(Value *V, char *NameStr) { } } if (Existing) { - if (Existing->getType() == V->getType()) { - // The type of the Existing value and the new one are the same. This - // is probably a type plane collapsing error. If the types involved - // are both integer, just rename it. Otherwise it - // is a redefinition error. - if (!Existing->getType()->isInteger()) { - error("Redefinition of value named '" + Name + "' in the '" + - V->getType()->getDescription() + "' type plane"); - return; - } + // An existing value of the same name was found. This might have happened + // because of the integer type planes collapsing in LLVM 2.0. + if (Existing->getType() == V->getType() && + !TypeHasInteger(Existing->getType())) { + // If the type does not contain any integers in them then this can't be + // a type plane collapsing issue. It truly is a redefinition and we + // should error out as the assembly is invalid. + error("Redefinition of value named '" + Name + "' of type '" + + V->getType()->getDescription() + "'"); + return; } // In LLVM 2.0 we don't allow names to be re-used for any values in a // function, regardless of Type. Previously re-use of names was okay as