6502/llvm-6502
1
0
Fork 0
mirror of https://github.com/c64scene-ar/llvm-6502.git synced 2025-07-31 09:25:42 +00:00
Code Issues Projects Releases Wiki Activity

rename Type::isIntegral to Type::isInteger, eliminating the old Type::isInteger.

Browse Source 
rename Type::getIntegralTypeMask to Type::getIntegerTypeMask.

This makes naming much more consistent.  For example, there are now no longer any
instances of IntegerType that are not considered isInteger! :)


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@33225 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Chris Lattner
2007-01-15 02:27:26 +00:00
parent b25c4ca9d8
commit 42a7551725
33 changed files with 241 additions and 247 deletions
Download Patch File Download Diff File Expand all files Collapse all files

6
lib/VMCore/AsmWriter.cpp
View File

@@ -222,7 +222,7 @@ static void fillTypeNameTable(const Module *M,
const Type *Ty = cast<Type>(TI->second);
if (!isa<PointerType>(Ty) ||
!cast<PointerType>(Ty)->getElementType()->isPrimitiveType() ||
!cast<PointerType>(Ty)->getElementType()->isIntegral() ||
!cast<PointerType>(Ty)->getElementType()->isInteger() ||
isa<OpaqueType>(cast<PointerType>(Ty)->getElementType()))
TypeNames.insert(std::make_pair(Ty, getLLVMName(TI->first)));
}
@@ -234,7 +234,7 @@ static void calcTypeName(const Type *Ty,
std::vector<const Type *> &TypeStack,
std::map<const Type *, std::string> &TypeNames,
std::string & Result){
if (Ty->isIntegral() || (Ty->isPrimitiveType() && !isa<OpaqueType>(Ty))) {
if (Ty->isInteger() || (Ty->isPrimitiveType() && !isa<OpaqueType>(Ty))) {
Result += Ty->getDescription(); // Base case
return;
}
@@ -353,7 +353,7 @@ static std::ostream &printTypeInt(std::ostream &Out, const Type *Ty,
// Primitive types always print out their description, regardless of whether
// they have been named or not.
//
if (Ty->isIntegral() || (Ty->isPrimitiveType() && !isa<OpaqueType>(Ty)))
if (Ty->isInteger() || (Ty->isPrimitiveType() && !isa<OpaqueType>(Ty)))
return Out << Ty->getDescription();
// Check to see if the type is named.