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Handle the case of a no-return invoke correctly. It actually still has
successors, they just are all landing pad successors. We handle this the same way as no successors. Comments attached for the next person to wade through here and another lovely test case courtesy of Benjamin Kramer's bugpoint reduction. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@145098 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -305,6 +305,14 @@ void MachineBasicBlock::updateTerminator() {
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assert(!TBB && "Found more than one non-landing-pad successor!");
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TBB = *SI;
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}
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// If there is no non-landing-pad successor, the block has no
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// fall-through edges to be concerned with.
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if (!TBB)
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return;
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// Finally update the unconditional successor to be reached via a branch
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// if it would not be reached by fallthrough.
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if (!isLayoutSuccessor(TBB))
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TII->InsertBranch(*this, TBB, 0, Cond, dl);
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}
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@ -504,6 +504,30 @@ loop:
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br label %loop
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}
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declare void @fake_throw() noreturn
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define void @test_eh_throw() {
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; For blocks containing a 'throw' (or similar functionality), we have
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; a no-return invoke. In this case, only EH successors will exist, and
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; fallthrough simply won't occur. Make sure we don't crash trying to update
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; terminators for such constructs.
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;
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; CHECK: test_eh_throw
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; CHECK: %entry
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; CHECK: %cleanup
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entry:
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invoke void @fake_throw() to label %continue unwind label %cleanup
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continue:
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unreachable
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cleanup:
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%0 = landingpad { i8*, i32 } personality i8* bitcast (i32 (...)* @__gxx_personality_v0 to i8*)
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cleanup
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unreachable
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}
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define void @test_unnatural_cfg_backwards_inner_loop() {
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; Test that when we encounter an unnatural CFG structure after having formed
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; a chain for an inner loop which happened to be laid out backwards we don't
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