Pass a && to getLazyBitcodeModule.

This forces callers to use std::move when calling it. It is somewhat odd to have
code with std::move that doesn't always move, but it is also odd to have code
without std::move that sometimes moves.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@217049 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Rafael Espindola
2014-09-03 17:31:46 +00:00
parent 38a4f3bbec
commit 6d66a1cd2f
7 changed files with 15 additions and 12 deletions

View File

@ -28,9 +28,9 @@ namespace llvm {
class raw_ostream;
/// Read the header of the specified bitcode buffer and prepare for lazy
/// deserialization of function bodies. If successful, this takes ownership
/// of 'buffer. On error, this *does not* take ownership of Buffer.
ErrorOr<Module *> getLazyBitcodeModule(std::unique_ptr<MemoryBuffer> &Buffer,
/// deserialization of function bodies. If successful, this moves Buffer. On
/// error, this *does not* move Buffer.
ErrorOr<Module *> getLazyBitcodeModule(std::unique_ptr<MemoryBuffer> &&Buffer,
LLVMContext &Context);
/// getStreamedBitcodeModule - Read the header of the specified stream