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Try fixing mingw build.

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git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@127153 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Argyrios Kyrtzidis 2011-03-07 05:35:01 +00:00
parent 9c9320426e
commit a36be82664
1 changed files with 15 additions and 27 deletions
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42
include/llvm/ADT/PointerUnion.h
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@ -19,29 +19,6 @@
namespace llvm {
/// \brief Statically get an integer for a type. For:
/// @code
/// PointerUnionTypeNum<PT1, PT2>::template NumFor<T>::Result
/// @endcode
/// Result will be 0 if T is PT1, 1 if it is PT2, and -1 otherwise.
template <typename PT1, typename PT2>
struct PointerUnionTypeNum {
private:
struct IsNeither { char x; };
struct IsPT1 { char x[2]; };
struct IsPT2 { char x[3]; };
static IsPT1 determine(PT1 *P);
static IsPT2 determine(PT2 *P);
static IsNeither determine(...);
public:
template <typename T>
struct NumFor {
static const int Result = (int)sizeof(determine((T*)0)) - 2;
};
};
template <typename T>
struct PointerUnionTypeSelectorReturn {
typedef T Return;
@ -105,6 +82,16 @@ namespace llvm {
PointerUnionUIntTraits<PT1,PT2> > ValTy;
private:
ValTy Val;
struct IsPT1 {
static const int Num = 0;
};
struct IsPT2 {
static const int Num = 1;
};
template <typename T>
struct UNION_DOESNT_CONTAIN_TYPE { };
public:
PointerUnion() {}
@ -127,10 +114,11 @@ namespace llvm {
/// is<T>() return true if the Union currently holds the type matching T.
template<typename T>
int is() const {
static const int TyNo =
::llvm::PointerUnionTypeNum<PT1, PT2>::template NumFor<T>::Result;
char TYPE_IS_NOT_IN_UNION[TyNo*2+1]; // statically check the type.
(void)TYPE_IS_NOT_IN_UNION;
typedef typename
::llvm::PointerUnionTypeSelector<PT1, T, IsPT1,
::llvm::PointerUnionTypeSelector<PT2, T, IsPT2,
UNION_DOESNT_CONTAIN_TYPE<T> > >::Return Ty;
int TyNo = Ty::Num;
return static_cast<int>(Val.getInt()) == TyNo;
}