Fix a crash in which a multiplication was being reported as being both negative

and positive: positive, because it could be directly computed to be positive;
negative, because the nsw flags means it is either negative or undefined (the
multiplication always overflowed).


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@145104 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Duncan Sands 2011-11-23 16:26:47 +00:00
parent f238f50aaf
commit a8f5cd3539
2 changed files with 24 additions and 2 deletions

View File

@ -248,9 +248,14 @@ void llvm::ComputeMaskedBits(Value *V, const APInt &Mask,
APInt::getHighBitsSet(BitWidth, LeadZ);
KnownZero &= Mask;
if (isKnownNonNegative)
// Only make use of no-wrap flags if we failed to compute the sign bit
// directly. This matters if the multiplication always overflows, in
// which case we prefer to follow the result of the direct computation,
// though as the program is invoking undefined behaviour we can choose
// whatever we like here.
if (isKnownNonNegative && !KnownOne.isNegative())
KnownZero.setBit(BitWidth - 1);
else if (isKnownNegative)
else if (isKnownNegative && !KnownZero.isNegative())
KnownOne.setBit(BitWidth - 1);
return;

View File

@ -0,0 +1,17 @@
; RUN: opt < %s -instsimplify
; The mul can be proved to always overflow (turning a negative value
; into a positive one) and thus results in undefined behaviour. At
; the same time we were deducing from the nsw flag that that mul could
; be assumed to have a negative value (since if not it has an undefined
; value, which can be taken to be negative). We were reporting the mul
; as being both positive and negative, firing an assertion!
define i1 @test1(i32 %a) {
entry:
%0 = or i32 %a, 1
%1 = shl i32 %0, 31
%2 = mul nsw i32 %1, 4
%3 = and i32 %2, -4
%4 = icmp ne i32 %3, 0
ret i1 %4
}