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Add an asserting ValueHandle to the block simplification code which will

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fire if anything ever invalidates the assumption of a terminator
instruction being unchanged throughout the routine.

I've convinced myself that the current definition of simplification
precludes such a transformation, so I think getting some asserts
coverage that we don't violate this agreement is sufficient to make this
code safe for the foreseeable future.

Comments to the contrary or other suggestions are of course welcome. =]
The bots are now happy with this code though, so it appears the bug here
has indeed been fixed.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@153401 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Chandler Carruth 2012-03-25 03:29:25 +00:00
parent eede6c9075
commit acdae3e25a
1 changed files with 9 additions and 0 deletions
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9
lib/Transforms/Utils/Local.cpp
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@ -355,6 +355,15 @@ bool llvm::RecursivelyDeleteDeadPHINode(PHINode *PN) {
/// instructions in other blocks as well in this block.
bool llvm::SimplifyInstructionsInBlock(BasicBlock *BB, const TargetData *TD) {
bool MadeChange = false;
#ifndef NDEBUG
// In debug builds, ensure that the terminator of the block is never replaced
// or deleted by these simplifications. The idea of simplification is that it
// cannot introduce new instructions, and there is no way to replace the
// terminator of a block without introducing a new instruction.
AssertingVH<Instruction> TerminatorVH(--BB->end());
#endif
for (BasicBlock::iterator BI = BB->begin(), E = --BB->end(); BI != E; ) {
assert(!BI->isTerminator());
Instruction *Inst = BI++;