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Fix an infinite loop where a transform in InstCombiner::visitAnd claims a construct is changed when it is not. (See included testcase.)
Patch by Xiaoyi Guo. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@140072 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -1174,30 +1174,31 @@ Instruction *InstCombiner::visitAnd(BinaryOperator &I) {
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((A == C && B == D) || (A == D && B == C)))
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return BinaryOperator::CreateXor(A, B);
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if (Op0->hasOneUse() &&
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match(Op0, m_Xor(m_Value(A), m_Value(B)))) {
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if (A == Op1) { // (A^B)&A -> A&(A^B)
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I.swapOperands(); // Simplify below
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std::swap(Op0, Op1);
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} else if (B == Op1) { // (A^B)&B -> B&(B^A)
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cast<BinaryOperator>(Op0)->swapOperands();
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I.swapOperands(); // Simplify below
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std::swap(Op0, Op1);
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// A&(A^B) => A & ~B
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{
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Value *tmpOp0 = Op0;
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Value *tmpOp1 = Op1;
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if (Op0->hasOneUse() &&
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match(Op0, m_Xor(m_Value(A), m_Value(B)))) {
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if (A == Op1 || B == Op1 ) {
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tmpOp1 = Op0;
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tmpOp0 = Op1;
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// Simplify below
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}
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}
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}
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if (Op1->hasOneUse() &&
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match(Op1, m_Xor(m_Value(A), m_Value(B)))) {
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if (B == Op0) { // B&(A^B) -> B&(B^A)
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cast<BinaryOperator>(Op1)->swapOperands();
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std::swap(A, B);
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if (tmpOp1->hasOneUse() &&
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match(tmpOp1, m_Xor(m_Value(A), m_Value(B)))) {
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if (B == tmpOp0) {
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std::swap(A, B);
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}
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// Notice that the patten (A&(~B)) is actually (A&(-1^B)), so if
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// A is originally -1 (or a vector of -1 and undefs), then we enter
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// an endless loop. By checking that A is non-constant we ensure that
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// we will never get to the loop.
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if (A == tmpOp0 && !isa<Constant>(A)) // A&(A^B) -> A & ~B
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return BinaryOperator::CreateAnd(A, Builder->CreateNot(B, "tmp"));
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}
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// Notice that the patten (A&(~B)) is actually (A&(-1^B)), so if
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// A is originally -1 (or a vector of -1 and undefs), then we enter
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// an endless loop. By checking that A is non-constant we ensure that
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// we will never get to the loop.
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if (A == Op0 && !isa<Constant>(A)) // A&(A^B) -> A & ~B
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return BinaryOperator::CreateAnd(A, Builder->CreateNot(B, "tmp"));
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}
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// (A&((~A)|B)) -> A&B
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@ -35,3 +35,10 @@ define i1 @test4(i32 %X) {
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; CHECK: @test4
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; CHECK-NEXT: ret i1 false
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}
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; Make sure we don't go into an infinite loop with this test
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define <4 x i32> @test5(<4 x i32> %A) {
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%1 = xor <4 x i32> %A, <i32 1, i32 2, i32 3, i32 4>
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%2 = and <4 x i32> <i32 1, i32 2, i32 3, i32 4>, %1
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ret <4 x i32> %2
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}
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