Reapply "InstrProf: Don't keep a large sparse list around just to zero it"

When I was preparing r218879 for commit, I removed an early return
that I decided was just noise. It wasn't. This is r218879 no-crash
edition.

This reverts commit r218881, reapplying r218879.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@218887 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Justin Bogner 2014-10-02 16:43:31 +00:00
parent f9e44c8bf8
commit ddc725b9b8
2 changed files with 50 additions and 32 deletions

View File

@ -103,8 +103,6 @@ struct CounterExpression {
class CounterExpressionBuilder {
/// \brief A list of all the counter expressions
llvm::SmallVector<CounterExpression, 16> Expressions;
/// \brief An array of terms used in expression simplification.
llvm::SmallVector<int, 16> Terms;
/// \brief Return the counter which corresponds to the given expression.
///
@ -113,18 +111,19 @@ class CounterExpressionBuilder {
/// expression is added to the builder's collection of expressions.
Counter get(const CounterExpression &E);
/// \brief Convert the expression tree represented by a counter
/// into a polynomial in the form of K1Counter1 + .. + KNCounterN
/// where K1 .. KN are integer constants that are stored in the Terms array.
void extractTerms(Counter C, int Sign = 1);
/// \brief Gather the terms of the expression tree for processing.
///
/// This collects each addition and subtraction referenced by the counter into
/// a sequence that can be sorted and combined to build a simplified counter
/// expression.
void extractTerms(Counter C, int Sign,
SmallVectorImpl<std::pair<unsigned, int>> &Terms);
/// \brief Simplifies the given expression tree
/// by getting rid of algebraically redundant operations.
Counter simplify(Counter ExpressionTree);
public:
CounterExpressionBuilder(unsigned NumCounterValues);
ArrayRef<CounterExpression> getExpressions() const { return Expressions; }
/// \brief Return a counter that represents the expression

View File

@ -27,10 +27,6 @@ using namespace coverage;
#define DEBUG_TYPE "coverage-mapping"
CounterExpressionBuilder::CounterExpressionBuilder(unsigned NumCounterValues) {
Terms.resize(NumCounterValues);
}
Counter CounterExpressionBuilder::get(const CounterExpression &E) {
for (unsigned I = 0, S = Expressions.size(); I < S; ++I) {
if (Expressions[I] == E)
@ -40,50 +36,73 @@ Counter CounterExpressionBuilder::get(const CounterExpression &E) {
return Counter::getExpression(Expressions.size() - 1);
}
void CounterExpressionBuilder::extractTerms(Counter C, int Sign) {
void CounterExpressionBuilder::extractTerms(
Counter C, int Sign, SmallVectorImpl<std::pair<unsigned, int>> &Terms) {
switch (C.getKind()) {
case Counter::Zero:
break;
case Counter::CounterValueReference:
Terms[C.getCounterID()] += Sign;
Terms.push_back(std::make_pair(C.getCounterID(), Sign));
break;
case Counter::Expression:
const auto &E = Expressions[C.getExpressionID()];
extractTerms(E.LHS, Sign);
extractTerms(E.RHS, E.Kind == CounterExpression::Subtract ? -Sign : Sign);
extractTerms(E.LHS, Sign, Terms);
extractTerms(E.RHS, E.Kind == CounterExpression::Subtract ? -Sign : Sign,
Terms);
break;
}
}
Counter CounterExpressionBuilder::simplify(Counter ExpressionTree) {
// Gather constant terms.
for (auto &I : Terms)
I = 0;
extractTerms(ExpressionTree);
llvm::SmallVector<std::pair<unsigned, int>, 32> Terms;
extractTerms(ExpressionTree, +1, Terms);
// If there are no terms, this is just a zero. The algorithm below assumes at
// least one term.
if (Terms.size() == 0)
return Counter::getZero();
// Group the terms by counter ID.
std::sort(Terms.begin(), Terms.end(),
[](const std::pair<unsigned, int> &LHS,
const std::pair<unsigned, int> &RHS) {
return LHS.first < RHS.first;
});
// Combine terms by counter ID to eliminate counters that sum to zero.
auto Prev = Terms.begin();
for (auto I = Prev + 1, E = Terms.end(); I != E; ++I) {
if (I->first == Prev->first) {
Prev->second += I->second;
continue;
}
++Prev;
*Prev = *I;
}
Terms.erase(++Prev, Terms.end());
Counter C;
// Create additions.
// Note: the additions are created first
// to avoid creation of a tree like ((0 - X) + Y) instead of (Y - X).
for (unsigned I = 0, S = Terms.size(); I < S; ++I) {
if (Terms[I] <= 0)
// Create additions. We do this before subtractions to avoid constructs like
// ((0 - X) + Y), as opposed to (Y - X).
for (auto Term : Terms) {
if (Term.second <= 0)
continue;
for (int J = 0; J < Terms[I]; ++J) {
for (int I = 0; I < Term.second; ++I)
if (C.isZero())
C = Counter::getCounter(I);
C = Counter::getCounter(Term.first);
else
C = get(CounterExpression(CounterExpression::Add, C,
Counter::getCounter(I)));
}
Counter::getCounter(Term.first)));
}
// Create subtractions.
for (unsigned I = 0, S = Terms.size(); I < S; ++I) {
if (Terms[I] >= 0)
for (auto Term : Terms) {
if (Term.second >= 0)
continue;
for (int J = 0; J < (-Terms[I]); ++J)
for (int I = 0; I < -Term.second; ++I)
C = get(CounterExpression(CounterExpression::Subtract, C,
Counter::getCounter(I)));
Counter::getCounter(Term.first)));
}
return C;
}