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Silly bug fix: Machine code vector could be empty for a no-op cast instruction,

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e.g., cast double to double.


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@3633 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Vikram S. Adve 2002-09-09 14:54:21 +00:00
parent 1d43fd4e83
commit ec7f482d90
1 changed files with 9 additions and 5 deletions
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14
lib/Target/SparcV9/SparcV9InstrSelection.cpp
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@ -1555,19 +1555,23 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
case 31: // reg: ToFloatTy(reg):
case 32: // reg: ToDoubleTy(reg):
case 232: // reg: ToDoubleTy(Constant):
// If this instruction has a parent (a user) in the tree
// and the user is translated as an FsMULd instruction,
// then the cast is unnecessary. So check that first.
// In the future, we'll want to do the same for the FdMULq instruction,
// so do the check here instead of only for ToFloatTy(reg).
//
if (subtreeRoot->parent() != NULL &&
MachineCodeForInstruction::get(((InstructionNode*)subtreeRoot->parent())->getInstruction())[0]->getOpCode() == FSMULD)
if (subtreeRoot->parent() != NULL)
{
forwardOperandNum = 0; // forward first operand to user
const MachineCodeForInstruction& mcfi =
MachineCodeForInstruction::get(
cast<InstructionNode>(subtreeRoot->parent())->getInstruction());
if (mcfi.size() == 0 || mcfi.front()->getOpCode() == FSMULD)
forwardOperandNum = 0; // forward first operand to user
}
else
if (forwardOperandNum != 0) // we do need the cast
{
Value* leftVal = subtreeRoot->leftChild()->getValue();
const Type* opType = leftVal->getType();