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gccld git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@1842 91177308-0d34-0410-b5e6-96231b3b80d8
117 lines
3.9 KiB
C
117 lines
3.9 KiB
C
//===-- atox.c - Ascii string parsers for LLVM libc Library -------*- C -*-===//
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//
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// A lot of this code is ripped gratuitously from glibc and libiberty.
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//
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//===----------------------------------------------------------------------===//
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#define isspace(x) ((x) == ' ' || (x) == '\t' || (x) == '\n')
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#define isdigit(x) ((x) >= '0' && (x) <= '9')
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#define isupper(x) ((x) >= 'A' && (x) <= 'Z')
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#define islower(x) ((x) >= 'a' && (x) <= 'z')
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#define isalpha(x) (isupper(x) || islower(x))
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#ifndef ULONG_MAX
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#define ULONG_MAX ((unsigned long)(~0L)) /* 0xFFFFFFFF */
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#endif
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#ifndef LONG_MAX
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#define LONG_MAX ((long)(ULONG_MAX >> 1)) /* 0x7FFFFFFF */
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#endif
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#ifndef LONG_MIN
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#define LONG_MIN ((long)(~LONG_MAX)) /* 0x80000000 */
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#endif
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/*
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* Convert a string to a long integer.
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*
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* Ignores `locale' stuff. Assumes that the upper and lower case
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* alphabets and digits are each contiguous.
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*/
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long strtol(const char *nptr, char **endptr, int base) {
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register const char *s = nptr;
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register unsigned long acc;
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register int c;
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register unsigned long cutoff;
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register int neg = 0, any, cutlim;
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/*
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* Skip white space and pick up leading +/- sign if any.
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* If base is 0, allow 0x for hex and 0 for octal, else
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* assume decimal; if base is already 16, allow 0x.
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*/
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do {
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c = *s++;
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} while (isspace(c));
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if (c == '-') {
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neg = 1;
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c = *s++;
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} else if (c == '+')
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c = *s++;
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if ((base == 0 || base == 16) &&
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c == '0' && (*s == 'x' || *s == 'X')) {
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c = s[1];
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s += 2;
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base = 16;
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}
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if (base == 0)
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base = c == '0' ? 8 : 10;
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/*
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* Compute the cutoff value between legal numbers and illegal
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* numbers. That is the largest legal value, divided by the
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* base. An input number that is greater than this value, if
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* followed by a legal input character, is too big. One that
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* is equal to this value may be valid or not; the limit
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* between valid and invalid numbers is then based on the last
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* digit. For instance, if the range for longs is
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* [-2147483648..2147483647] and the input base is 10,
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* cutoff will be set to 214748364 and cutlim to either
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* 7 (neg==0) or 8 (neg==1), meaning that if we have accumulated
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* a value > 214748364, or equal but the next digit is > 7 (or 8),
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* the number is too big, and we will return a range error.
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*
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* Set any if any `digits' consumed; make it negative to indicate
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* overflow.
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*/
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cutoff = neg ? -(unsigned long)LONG_MIN : LONG_MAX;
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cutlim = cutoff % (unsigned long)base;
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cutoff /= (unsigned long)base;
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for (acc = 0, any = 0;; c = *s++) {
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if (isdigit(c))
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c -= '0';
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else if (isalpha(c))
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c -= isupper(c) ? 'A' - 10 : 'a' - 10;
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else
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break;
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if (c >= base)
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break;
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if (any < 0 || acc > cutoff || acc == cutoff && c > cutlim)
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any = -1;
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else {
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any = 1;
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acc *= base;
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acc += c;
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}
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}
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if (any < 0) {
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acc = neg ? LONG_MIN : LONG_MAX;
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} else if (neg)
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acc = -acc;
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if (endptr != 0)
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*endptr = (char *) (any ? s - 1 : nptr);
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return (acc);
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}
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/* Convert a string to an int. */
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int atoi(const char *nptr) {
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return (int)strtol(nptr, 0, 10);
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}
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/* Convert a string to a long int. */
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long int atol(const char *nptr) {
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return strtol(nptr, 0, 10);
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}
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