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0f9fd5b0f8
By making sure to consider binary expressions identical if their operands are backwards, but swappable. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@2629 91177308-0d34-0410-b5e6-96231b3b80d8
464 lines
18 KiB
C++
464 lines
18 KiB
C++
//===-- GCSE.cpp - SSA based Global Common Subexpr Elimination ------------===//
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//
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// This pass is designed to be a very quick global transformation that
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// eliminates global common subexpressions from a function. It does this by
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// examining the SSA value graph of the function, instead of doing slow, dense,
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// bit-vector computations.
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//
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// This pass works best if it is proceeded with a simple constant propogation
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// pass and an instruction combination pass because this pass does not do any
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// value numbering (in order to be speedy).
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//
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// This pass does not attempt to CSE load instructions, because it does not use
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// pointer analysis to determine when it is safe.
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//
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//===----------------------------------------------------------------------===//
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#include "llvm/Transforms/Scalar.h"
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#include "llvm/InstrTypes.h"
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#include "llvm/iMemory.h"
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#include "llvm/Analysis/Dominators.h"
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#include "llvm/Support/InstVisitor.h"
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#include "llvm/Support/InstIterator.h"
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#include "llvm/Support/CFG.h"
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#include "Support/StatisticReporter.h"
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#include <algorithm>
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static Statistic<> NumInstRemoved("gcse\t\t- Number of instructions removed");
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static Statistic<> NumLoadRemoved("gcse\t\t- Number of loads removed");
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namespace {
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class GCSE : public FunctionPass, public InstVisitor<GCSE, bool> {
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set<Instruction*> WorkList;
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DominatorSet *DomSetInfo;
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ImmediateDominators *ImmDominator;
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// BBContainsStore - Contains a value that indicates whether a basic block
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// has a store or call instruction in it. This map is demand populated, so
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// not having an entry means that the basic block has not been scanned yet.
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//
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map<BasicBlock*, bool> BBContainsStore;
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public:
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const char *getPassName() const {
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return "Global Common Subexpression Elimination";
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}
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virtual bool runOnFunction(Function *F);
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// Visitation methods, these are invoked depending on the type of
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// instruction being checked. They should return true if a common
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// subexpression was folded.
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//
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bool visitUnaryOperator(Instruction *I);
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bool visitBinaryOperator(Instruction *I);
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bool visitGetElementPtrInst(GetElementPtrInst *I);
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bool visitCastInst(CastInst *I){return visitUnaryOperator((Instruction*)I);}
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bool visitShiftInst(ShiftInst *I) {
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return visitBinaryOperator((Instruction*)I);
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}
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bool visitLoadInst(LoadInst *LI);
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bool visitInstruction(Instruction *) { return false; }
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private:
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void ReplaceInstWithInst(Instruction *First, BasicBlock::iterator SI);
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void CommonSubExpressionFound(Instruction *I, Instruction *Other);
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// TryToRemoveALoad - Try to remove one of L1 or L2. The problem with
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// removing loads is that intervening stores might make otherwise identical
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// load's yield different values. To ensure that this is not the case, we
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// check that there are no intervening stores or calls between the
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// instructions.
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//
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bool TryToRemoveALoad(LoadInst *L1, LoadInst *L2);
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// CheckForInvalidatingInst - Return true if BB or any of the predecessors
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// of BB (until DestBB) contain a store (or other invalidating) instruction.
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//
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bool CheckForInvalidatingInst(BasicBlock *BB, BasicBlock *DestBB,
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set<BasicBlock*> &VisitedSet);
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// This transformation requires dominator and immediate dominator info
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virtual void getAnalysisUsage(AnalysisUsage &AU) const {
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AU.preservesCFG();
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AU.addRequired(DominatorSet::ID);
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AU.addRequired(ImmediateDominators::ID);
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}
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};
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}
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// createGCSEPass - The public interface to this file...
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Pass *createGCSEPass() { return new GCSE(); }
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// GCSE::runOnFunction - This is the main transformation entry point for a
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// function.
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//
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bool GCSE::runOnFunction(Function *F) {
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bool Changed = false;
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DomSetInfo = &getAnalysis<DominatorSet>();
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ImmDominator = &getAnalysis<ImmediateDominators>();
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// Step #1: Add all instructions in the function to the worklist for
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// processing. All of the instructions are considered to be our
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// subexpressions to eliminate if possible.
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//
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WorkList.insert(inst_begin(F), inst_end(F));
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// Step #2: WorkList processing. Iterate through all of the instructions,
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// checking to see if there are any additionally defined subexpressions in the
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// program. If so, eliminate them!
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//
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while (!WorkList.empty()) {
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Instruction *I = *WorkList.begin(); // Get an instruction from the worklist
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WorkList.erase(WorkList.begin());
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// Visit the instruction, dispatching to the correct visit function based on
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// the instruction type. This does the checking.
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//
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Changed |= visit(I);
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}
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// Clear out data structure so that next function starts fresh
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BBContainsStore.clear();
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// When the worklist is empty, return whether or not we changed anything...
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return Changed;
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}
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// ReplaceInstWithInst - Destroy the instruction pointed to by SI, making all
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// uses of the instruction use First now instead.
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//
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void GCSE::ReplaceInstWithInst(Instruction *First, BasicBlock::iterator SI) {
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Instruction *Second = *SI;
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//cerr << "DEL " << (void*)Second << Second;
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// Add the first instruction back to the worklist
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WorkList.insert(First);
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// Add all uses of the second instruction to the worklist
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for (Value::use_iterator UI = Second->use_begin(), UE = Second->use_end();
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UI != UE; ++UI)
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WorkList.insert(cast<Instruction>(*UI));
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// Make all users of 'Second' now use 'First'
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Second->replaceAllUsesWith(First);
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// Erase the second instruction from the program
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delete Second->getParent()->getInstList().remove(SI);
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}
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// CommonSubExpressionFound - The two instruction I & Other have been found to
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// be common subexpressions. This function is responsible for eliminating one
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// of them, and for fixing the worklist to be correct.
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//
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void GCSE::CommonSubExpressionFound(Instruction *I, Instruction *Other) {
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assert(I != Other);
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WorkList.erase(I);
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WorkList.erase(Other); // Other may not actually be on the worklist anymore...
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++NumInstRemoved; // Keep track of number of instructions eliminated
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// Handle the easy case, where both instructions are in the same basic block
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BasicBlock *BB1 = I->getParent(), *BB2 = Other->getParent();
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if (BB1 == BB2) {
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// Eliminate the second occuring instruction. Add all uses of the second
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// instruction to the worklist.
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//
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// Scan the basic block looking for the "first" instruction
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BasicBlock::iterator BI = BB1->begin();
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while (*BI != I && *BI != Other) {
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++BI;
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assert(BI != BB1->end() && "Instructions not found in parent BB!");
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}
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// Keep track of which instructions occurred first & second
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Instruction *First = *BI;
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Instruction *Second = I != First ? I : Other; // Get iterator to second inst
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BI = find(BI, BB1->end(), Second);
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assert(BI != BB1->end() && "Second instruction not found in parent block!");
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// Destroy Second, using First instead.
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ReplaceInstWithInst(First, BI);
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// Otherwise, the two instructions are in different basic blocks. If one
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// dominates the other instruction, we can simply use it
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//
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} else if (DomSetInfo->dominates(BB1, BB2)) { // I dom Other?
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BasicBlock::iterator BI = find(BB2->begin(), BB2->end(), Other);
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assert(BI != BB2->end() && "Other not in parent basic block!");
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ReplaceInstWithInst(I, BI);
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} else if (DomSetInfo->dominates(BB2, BB1)) { // Other dom I?
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BasicBlock::iterator BI = find(BB1->begin(), BB1->end(), I);
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assert(BI != BB1->end() && "I not in parent basic block!");
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ReplaceInstWithInst(Other, BI);
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} else {
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// Handle the most general case now. In this case, neither I dom Other nor
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// Other dom I. Because we are in SSA form, we are guaranteed that the
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// operands of the two instructions both dominate the uses, so we _know_
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// that there must exist a block that dominates both instructions (if the
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// operands of the instructions are globals or constants, worst case we
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// would get the entry node of the function). Search for this block now.
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//
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// Search up the immediate dominator chain of BB1 for the shared dominator
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BasicBlock *SharedDom = (*ImmDominator)[BB1];
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while (!DomSetInfo->dominates(SharedDom, BB2))
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SharedDom = (*ImmDominator)[SharedDom];
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// At this point, shared dom must dominate BOTH BB1 and BB2...
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assert(SharedDom && DomSetInfo->dominates(SharedDom, BB1) &&
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DomSetInfo->dominates(SharedDom, BB2) && "Dominators broken!");
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// Rip 'I' out of BB1, and move it to the end of SharedDom.
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BB1->getInstList().remove(I);
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SharedDom->getInstList().insert(SharedDom->end()-1, I);
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// Eliminate 'Other' now.
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BasicBlock::iterator BI = find(BB2->begin(), BB2->end(), Other);
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assert(BI != BB2->end() && "I not in parent basic block!");
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ReplaceInstWithInst(I, BI);
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}
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}
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//===----------------------------------------------------------------------===//
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//
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// Visitation methods, these are invoked depending on the type of instruction
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// being checked. They should return true if a common subexpression was folded.
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//
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//===----------------------------------------------------------------------===//
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bool GCSE::visitUnaryOperator(Instruction *I) {
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Value *Op = I->getOperand(0);
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Function *F = I->getParent()->getParent();
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for (Value::use_iterator UI = Op->use_begin(), UE = Op->use_end();
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UI != UE; ++UI)
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if (Instruction *Other = dyn_cast<Instruction>(*UI))
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// Check to see if this new binary operator is not I, but same operand...
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if (Other != I && Other->getOpcode() == I->getOpcode() &&
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Other->getOperand(0) == Op && // Is the operand the same?
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// Is it embeded in the same function? (This could be false if LHS
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// is a constant or global!)
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Other->getParent()->getParent() == F &&
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// Check that the types are the same, since this code handles casts...
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Other->getType() == I->getType()) {
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// These instructions are identical. Handle the situation.
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CommonSubExpressionFound(I, Other);
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return true; // One instruction eliminated!
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}
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return false;
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}
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// isIdenticalBinaryInst - Return true if the two binary instructions are
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// identical.
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//
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static inline bool isIdenticalBinaryInst(const Instruction *I1,
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const Instruction *I2) {
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// Is it embeded in the same function? (This could be false if LHS
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// is a constant or global!)
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if (I1->getOpcode() != I2->getOpcode() ||
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I1->getParent()->getParent() != I2->getParent()->getParent())
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return false;
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// They are identical if both operands are the same!
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if (I1->getOperand(0) == I2->getOperand(0) &&
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I1->getOperand(1) == I2->getOperand(1))
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return true;
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// If the instruction is commutative and associative, the instruction can
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// match if the operands are swapped!
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//
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if ((I1->getOperand(0) == I2->getOperand(1) &&
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I1->getOperand(1) == I2->getOperand(0)) &&
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(I1->getOpcode() == Instruction::Add ||
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I1->getOpcode() == Instruction::Mul ||
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I1->getOpcode() == Instruction::And ||
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I1->getOpcode() == Instruction::Or ||
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I1->getOpcode() == Instruction::Xor))
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return true;
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return false;
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}
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bool GCSE::visitBinaryOperator(Instruction *I) {
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Value *LHS = I->getOperand(0), *RHS = I->getOperand(1);
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Function *F = I->getParent()->getParent();
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for (Value::use_iterator UI = LHS->use_begin(), UE = LHS->use_end();
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UI != UE; ++UI)
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if (Instruction *Other = dyn_cast<Instruction>(*UI))
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// Check to see if this new binary operator is not I, but same operand...
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if (Other != I && isIdenticalBinaryInst(I, Other)) {
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// These instructions are identical. Handle the situation.
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CommonSubExpressionFound(I, Other);
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return true; // One instruction eliminated!
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}
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return false;
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}
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// IdenticalComplexInst - Return true if the two instructions are the same, by
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// using a brute force comparison.
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//
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static bool IdenticalComplexInst(const Instruction *I1, const Instruction *I2) {
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assert(I1->getOpcode() == I2->getOpcode());
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// Equal if they are in the same function...
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return I1->getParent()->getParent() == I2->getParent()->getParent() &&
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// And return the same type...
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I1->getType() == I2->getType() &&
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// And have the same number of operands...
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I1->getNumOperands() == I2->getNumOperands() &&
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// And all of the operands are equal.
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std::equal(I1->op_begin(), I1->op_end(), I2->op_begin());
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}
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bool GCSE::visitGetElementPtrInst(GetElementPtrInst *I) {
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Value *Op = I->getOperand(0);
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Function *F = I->getParent()->getParent();
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for (Value::use_iterator UI = Op->use_begin(), UE = Op->use_end();
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UI != UE; ++UI)
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if (GetElementPtrInst *Other = dyn_cast<GetElementPtrInst>(*UI))
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// Check to see if this new getelementptr is not I, but same operand...
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if (Other != I && IdenticalComplexInst(I, Other)) {
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// These instructions are identical. Handle the situation.
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CommonSubExpressionFound(I, Other);
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return true; // One instruction eliminated!
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}
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return false;
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}
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bool GCSE::visitLoadInst(LoadInst *LI) {
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Value *Op = LI->getOperand(0);
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Function *F = LI->getParent()->getParent();
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for (Value::use_iterator UI = Op->use_begin(), UE = Op->use_end();
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UI != UE; ++UI)
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if (LoadInst *Other = dyn_cast<LoadInst>(*UI))
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// Check to see if this new load is not LI, but has the same operands...
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if (Other != LI && IdenticalComplexInst(LI, Other) &&
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TryToRemoveALoad(LI, Other))
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return true; // An instruction was eliminated!
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return false;
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}
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static inline bool isInvalidatingInst(const Instruction *I) {
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return I->getOpcode() == Instruction::Store ||
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I->getOpcode() == Instruction::Call ||
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I->getOpcode() == Instruction::Invoke;
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}
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// TryToRemoveALoad - Try to remove one of L1 or L2. The problem with removing
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// loads is that intervening stores might make otherwise identical load's yield
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// different values. To ensure that this is not the case, we check that there
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// are no intervening stores or calls between the instructions.
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//
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bool GCSE::TryToRemoveALoad(LoadInst *L1, LoadInst *L2) {
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// Figure out which load dominates the other one. If neither dominates the
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// other we cannot eliminate one...
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//
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if (DomSetInfo->dominates(L2, L1))
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std::swap(L1, L2); // Make L1 dominate L2
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else if (!DomSetInfo->dominates(L1, L2))
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return false; // Neither instruction dominates the other one...
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BasicBlock *BB1 = L1->getParent(), *BB2 = L2->getParent();
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// FIXME: This is incredibly painful with broken rep
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BasicBlock::iterator L1I = std::find(BB1->begin(), BB1->end(), L1);
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assert(L1I != BB1->end() && "Inst not in own parent?");
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// L1 now dominates L2. Check to see if the intervening instructions between
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// the two loads include a store or call...
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//
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if (BB1 == BB2) { // In same basic block?
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// In this degenerate case, no checking of global basic blocks has to occur
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// just check the instructions BETWEEN L1 & L2...
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//
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for (++L1I; *L1I != L2; ++L1I)
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if (isInvalidatingInst(*L1I))
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return false; // Cannot eliminate load
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++NumLoadRemoved;
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CommonSubExpressionFound(L1, L2);
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return true;
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} else {
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// Make sure that there are no store instructions between L1 and the end of
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// it's basic block...
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//
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for (++L1I; L1I != BB1->end(); ++L1I)
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if (isInvalidatingInst(*L1I)) {
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BBContainsStore[BB1] = true;
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return false; // Cannot eliminate load
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}
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// Make sure that there are no store instructions between the start of BB2
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// and the second load instruction...
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//
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for (BasicBlock::iterator II = BB2->begin(); *II != L2; ++II)
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if (isInvalidatingInst(*II)) {
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BBContainsStore[BB2] = true;
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return false; // Cannot eliminate load
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}
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// Do a depth first traversal of the inverse CFG starting at L2's block,
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// looking for L1's block. The inverse CFG is made up of the predecessor
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// nodes of a block... so all of the edges in the graph are "backward".
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//
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set<BasicBlock*> VisitedSet;
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for (pred_iterator PI = pred_begin(BB2), PE = pred_end(BB2); PI != PE; ++PI)
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if (CheckForInvalidatingInst(*PI, BB1, VisitedSet))
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return false;
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++NumLoadRemoved;
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CommonSubExpressionFound(L1, L2);
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return true;
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}
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return false;
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}
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// CheckForInvalidatingInst - Return true if BB or any of the predecessors of BB
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// (until DestBB) contain a store (or other invalidating) instruction.
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//
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bool GCSE::CheckForInvalidatingInst(BasicBlock *BB, BasicBlock *DestBB,
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set<BasicBlock*> &VisitedSet) {
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// Found the termination point!
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if (BB == DestBB || VisitedSet.count(BB)) return false;
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// Avoid infinite recursion!
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VisitedSet.insert(BB);
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// Have we already checked this block?
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map<BasicBlock*, bool>::iterator MI = BBContainsStore.find(BB);
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if (MI != BBContainsStore.end()) {
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// If this block is known to contain a store, exit the recursion early...
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if (MI->second) return true;
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// Otherwise continue checking predecessors...
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} else {
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// We don't know if this basic block contains an invalidating instruction.
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// Check now:
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bool HasStore = std::find_if(BB->begin(), BB->end(),
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isInvalidatingInst) != BB->end();
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if ((BBContainsStore[BB] = HasStore)) // Update map
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return true; // Exit recursion early...
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}
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// Check all of our predecessor blocks...
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for (pred_iterator PI = pred_begin(BB), PE = pred_end(BB); PI != PE; ++PI)
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if (CheckForInvalidatingInst(*PI, DestBB, VisitedSet))
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return true;
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// None of our predecessor blocks contain a store, and we don't either!
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return false;
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}
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