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if ((a & 0x1) == 0x1) { .. } In this case we don't actually have any branch probability information and should not assume to have any. LLVM transforms this into: %and = and i32 %a, 1 %tobool = icmp eq i32 %and, 0 So, in this case, the result of a bitwise and is compared against 0, but nevertheless, we should not assume to have probability information. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@234898 91177308-0d34-0410-b5e6-96231b3b80d8 |
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