if ((a & 0x1) == 0x1) {
..
}
In this case we don't actually have any branch probability information and
should not assume to have any. LLVM transforms this into:
%and = and i32 %a, 1
%tobool = icmp eq i32 %and, 0
So, in this case, the result of a bitwise and is compared against 0,
but nevertheless, we should not assume to have probability
information.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@234898 91177308-0d34-0410-b5e6-96231b3b80d8