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- (A & C1)+(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0 - (A & C1)^(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0 git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@5741 91177308-0d34-0410-b5e6-96231b3b80d8
60 lines
1.2 KiB
LLVM
60 lines
1.2 KiB
LLVM
; This test makes sure that add instructions are properly eliminated.
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;
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; This also tests that a subtract with a constant is properly converted
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; to a add w/negative constant
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; RUN: if as < %s | opt -instcombine -die | dis | grep add
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; RUN: then exit 1
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; RUN: else exit 0
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; RUN: fi
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implementation
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int %test1(int %A) {
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%B = add int %A, 0
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ret int %B
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}
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int %test2(int %A) {
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%B = add int %A, 5
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%C = add int %B, -5
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ret int %C
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}
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int %test3(int %A) {
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%B = add int %A, 5
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%C = sub int %B, 5 ;; This should get converted to an add
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ret int %C
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}
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int %test4(int %A, int %B) {
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%C = sub int 0, %A
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%D = add int %B, %C ; D = B + -A = B - A
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ret int %D
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}
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int %test5(int %A, int %B) {
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%C = sub int 0, %A
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%D = add int %C, %B ; D = -A + B = B - A
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ret int %D
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}
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int %test6(int %A) {
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%B = mul int 7, %A
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%C = add int %B, %A ; C = 7*A+A == 8*A == A << 3
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ret int %C
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}
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int %test7(int %A) {
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%B = mul int 7, %A
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%C = add int %A, %B ; C = A+7*A == 8*A == A << 3
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ret int %C
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}
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int %test8(int %A, int %B) { ; (A & C1)+(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
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%A1 = and int %A, 7
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%B1 = and int %B, 128
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%C = add int %A1, %B1
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ret int %C
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}
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