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consider: C1 = INT_MIN C2 = -1 C1 * C2 overflows without a doubt but consider the following: %x = i32 INT_MIN This means that (%X /s C1) is 1 and (%X /s C1) /s C2 is -1. N. B. Move the unsigned version of this transform to InstSimplify, it doesn't create any new instructions. This fixes PR21243. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@219567 91177308-0d34-0410-b5e6-96231b3b80d8 |
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Hello | ||
InstCombine | ||
Instrumentation | ||
IPO | ||
ObjCARC | ||
Scalar | ||
Utils | ||
Vectorize | ||
CMakeLists.txt | ||
LLVMBuild.txt | ||
Makefile |