llvm-6502/lib/Object/YAML.cpp
Rafael Espindola 149d1a1894 Use isxdigit.
Thanks to Benjamin Kramer for the suggestion.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@183540 91177308-0d34-0410-b5e6-96231b3b80d8
2013-06-07 18:05:03 +00:00

63 lines
2.0 KiB
C++

//===- YAML.cpp - YAMLIO utilities for object files -----------------------===//
//
// The LLVM Compiler Infrastructure
//
// This file is distributed under the University of Illinois Open Source
// License. See LICENSE.TXT for details.
//
//===----------------------------------------------------------------------===//
//
// This file defines utility classes for handling the YAML representation of
// object files.
//
//===----------------------------------------------------------------------===//
#include "llvm/Object/YAML.h"
#include "llvm/Support/raw_ostream.h"
using namespace llvm;
using namespace object::yaml;
void yaml::ScalarTraits<object::yaml::BinaryRef>::output(
const object::yaml::BinaryRef &Val, void *, llvm::raw_ostream &Out) {
Val.writeAsHex(Out);
}
StringRef yaml::ScalarTraits<object::yaml::BinaryRef>::input(
StringRef Scalar, void *, object::yaml::BinaryRef &Val) {
if (Scalar.size() % 2 != 0)
return "BinaryRef hex string must contain an even number of nybbles.";
// TODO: Can we improve YAMLIO to permit a more accurate diagnostic here?
// (e.g. a caret pointing to the offending character).
for (unsigned I = 0, N = Scalar.size(); I != N; ++I)
if (!isxdigit(Scalar[I]))
return "BinaryRef hex string must contain only hex digits.";
Val = object::yaml::BinaryRef(Scalar);
return StringRef();
}
void BinaryRef::writeAsBinary(raw_ostream &OS) const {
if (!DataIsHexString) {
OS.write((const char *)Data.data(), Data.size());
return;
}
for (unsigned I = 0, N = Data.size(); I != N; I += 2) {
uint8_t Byte;
StringRef((const char *)&Data[I], 2).getAsInteger(16, Byte);
OS.write(Byte);
}
}
void BinaryRef::writeAsHex(raw_ostream &OS) const {
if (DataIsHexString) {
OS.write((const char *)Data.data(), Data.size());
return;
}
for (ArrayRef<uint8_t>::iterator I = Data.begin(), E = Data.end(); I != E;
++I) {
uint8_t Byte = *I;
OS << hexdigit(Byte >> 4);
OS << hexdigit(Byte & 0xf);
}
}