1
0
mirror of https://github.com/mgcaret/of816.git synced 2024-12-29 17:31:57 +00:00
of816/asm/mathlib.s

384 lines
10 KiB
ArmAsm
Raw Normal View History

2019-07-01 17:33:44 +00:00
; Math Library - I don't reinvent the wheel here for multiplication, division, etc.
; others have done great work before me and I credit them when I know who did it.
; 32-bit signed comparison
; C and Z reflect same comparision results as CMP instruction
.proc _stest32
lda STACKBASE+6,x
eor STACKBASE+2,x
bpl samesign
2020-01-04 03:41:25 +00:00
lda STACKBASE+2,x ; Kelvin's excellent solution
sec
rol
2019-07-01 17:33:44 +00:00
rts
samesign: lda STACKBASE+6,x
cmp STACKBASE+2,x
bcc :+ ; less than or not equal, done
bne :+
lda STACKBASE+4,x
cmp STACKBASE+0,x
: rts
.endproc
2020-01-05 00:25:41 +00:00
_test32 = _stest32::samesign
2019-07-01 17:33:44 +00:00
.proc _invertay
pha
tya
eor #$FFFF
tay
pla
eor #$FFFF
rts
.endproc
.proc _negateay
pha
tya
eor #$FFFF
clc
adc #$0001
tay
pla
eor #$FFFF
adc #$0000
rts
.endproc
.proc _invert
lda STACKBASE+0,x
eor #$FFFF
sta STACKBASE+0,x
lda STACKBASE+2,x
eor #$FFFF
sta STACKBASE+2,x
rts
.endproc
.proc _negate
jsr _invert
inc STACKBASE+0,x
bne :+
inc STACKBASE+2,x
: rts
.endproc
.proc _dinvert
jsr _invert
lda STACKBASE+4,x
eor #$FFFF
sta STACKBASE+4,x
lda STACKBASE+6,x
eor #$FFFF
sta STACKBASE+6,x
rts
.endproc
.proc _dnegate
jsr _dinvert
inc STACKBASE+4,x
bne :+
inc STACKBASE+6,x
bne :+
inc STACKBASE+0,x
bne :+
inc STACKBASE+2,x
: rts
.endproc
.proc _2abs
bit STACKBASE+2,x
bpl :+
jsr _negate
: jsr _swap
; fall-through
.endproc
.proc _abs
bit STACKBASE+2,x
bpl :+
jsr _negate
: rts
.endproc
.proc _signum
ldy #$FFFF
lda STACKBASE+2,x
bpl :+
sty STACKBASE+2,x
bra done
: iny
stz STACKBASE+2,x
ora STACKBASE+0,x
beq done
iny
done: sty STACKBASE+0,x
rts
.endproc
; 32-bit unsigned multiplication with 64-bit result
; right-shifting version by dclxvi
; scratch in YR, YR+2 (preserved)
.proc _umult
N = YR
lda N+2
pha
lda N
pha
lda #$00
sta N
ldy #32
lsr STACKBASE+6,x
ror STACKBASE+4,x
l1: bcc l2
clc
sta N+2
lda N
adc STACKBASE+0,x
sta N
lda N+2
adc STACKBASE+2,x
l2: ror
ror N
ror STACKBASE+6,x
ror STACKBASE+4,x
dey
bne l1
sta STACKBASE+2,x
lda N
sta STACKBASE+0,x
pla
sta N
pla
sta N+2
rts
.endproc
; 64-bit divided by 32-bit with 32-bit quotient and remainder
; Adapted from Garth's routine, just like everyone else :-)
; carry set if divison by zero or overflow
; ( d n -- r q )
; d.hi = stack(4,6), d.low = stack(8,10), n=stack(0,2)
.proc _umdivmod
CARRY = YR
SCRATCH = YR+2
.if 1 ; shortcut 32-bit by 32-bit division
lda STACKBASE+4,x
ora STACKBASE+6,x
beq _udivmod32 ; go do faster 32-bit divide
.endif
lda SCRATCH
pha
lda CARRY
pha
sec ; first, check for overflow and division by 0
lda STACKBASE+4,x
sbc STACKBASE+0,x
lda STACKBASE+6,x
sbc STACKBASE+2,x
bcs overflow
lda #33 ; 32 bits + 1
sta XR
loop: rol STACKBASE+8,x
rol STACKBASE+10,x
dec XR
beq done
rol STACKBASE+4,x
rol STACKBASE+6,x
stz CARRY
rol CARRY
sec
lda STACKBASE+4,x
sbc STACKBASE+0,x
sta SCRATCH
lda STACKBASE+6,x
sbc STACKBASE+2,x
tay
lda CARRY
sbc #0
bcc loop
lda SCRATCH
sta STACKBASE+4,x
sty STACKBASE+6,x
bra loop
overflow: sec
bra done1
done: clc
inx ; drop
inx
inx
inx
done1: pla
sta CARRY
pla
sta SCRATCH
bcs :+ ; leave stack intact if exception
jmp _swap1
: rts
.endproc
; 32-bit by 32-bit division
; assumes that the second stack entry is zero
; ( d n -- r q ) where d.hi is zero e.g. ( n1 0 n2 -- r q )
; d.hi = stack(4,6) = 0, d.low = n1 = stack(8,10), n2 = stack(0,2)
.proc _udivmod32
lda #32
sta XR
l1: asl STACKBASE+8,x ; shift high bit of n1 into r
rol STACKBASE+10,x ; clearing the low bit for q
rol STACKBASE+4,x ; r.lo
rol STACKBASE+6,x ; r.hi
lda STACKBASE+4,x ; r.lo
sec ; trial subraction
sbc STACKBASE+0,x ; n2.lo
tay ; save low word
lda STACKBASE+6,x ; r.hi
sbc STACKBASE+2,x ; n2.hi
bcc l2 ; subtraction succeeded?
sta STACKBASE+6,x ; r.hi yes, save result
sty STACKBASE+4,x ; r.lo
inc STACKBASE+8,x ; n1.lo and record a 1 in the quotient
l2: dec XR ; next bit
bne l1
inx ; kill of top stack item
inx
inx
inx
clc ; this *never* overflows
jmp _swap1
.endproc
; ( d n -- ud u )
.proc _dnabs
lda STACKBASE+2,x ; take absolute value of n1
2020-03-23 00:11:32 +00:00
bpl :+ ; if needed
2019-07-01 17:33:44 +00:00
jsr _negate
: lda STACKBASE+6,x ; take absolute value of d
2020-03-23 00:11:32 +00:00
bpl :+ ; if needed
2019-07-01 17:33:44 +00:00
dtneg: inx
inx
inx
inx
jsr _dnegate
dex
dex
dex
dex
: rts
.endproc
_dtucknegate = _dnabs::dtneg
.proc _smdivrem
lda STACKBASE+6,x ; save dividend sign in MSW of high cell of d
pha
eor STACKBASE+2,x ; compute result sign and save
pha
jsr _dnabs ; take absolute value of arguments
jsr _umdivmod
bcs overflow ; overflow
pla ; see if we should negate quotient
bpl :+
jsr _negate ; make it negative
: pla ; get dividend sign
bpl :+
tneg: inx ; negate remainder if it should be negative
inx
inx
inx
jsr _negate
dex
dex
dex
dex
: clc
rts
overflow: pla ; carry is set, pla does not affect it
pla
rts
.endproc
_tucknegate = _smdivrem::tneg
2020-03-23 00:11:32 +00:00
; ( d1 n1 -- n2 n3 )
; Divide dividend d1 by divisor n1, giving the floored quotient n3 and the remainder n2.
; Input and output stack arguments are signed.
2019-07-01 17:33:44 +00:00
.proc _fmdivmod
2020-03-23 00:11:32 +00:00
lda STACKBASE+2,x ; high word of n1
pha ; save divisor sign
2019-07-01 17:33:44 +00:00
bpl :+
2020-03-23 00:11:32 +00:00
jsr _negate ; negate both if n1 was negative
jsr _dtucknegate
: lda STACKBASE+6,x ; highest word of d1
2019-07-01 17:33:44 +00:00
bpl :+
2020-03-23 00:11:32 +00:00
lda STACKBASE+0,x ; it's negative, add n1 to high cell of d1
2019-07-01 17:33:44 +00:00
clc
adc STACKBASE+4,x
sta STACKBASE+4,x
lda STACKBASE+2,x
adc STACKBASE+6,x
sta STACKBASE+6,x
2020-03-23 00:11:32 +00:00
: jsr _umdivmod ; UM/MOD
pla ; get divisor sign back (carry unaffected)
bcs :+ ; error
bpl :+ ; if n1 was positive
jsr _tucknegate ; if it was, negate the result (clears carry)
2019-07-01 17:33:44 +00:00
: rts
.endproc
; adapted from Lee Davidson routine
; ( u1 -- u1 u2 ) u1 = closest integer <= square root, u2 = remainder
; number popped into WR,WR+2
; remainder on stack, offsets 0,2
; root on stack, offsets 4,6
; temp in YR
; counter in XR
.proc _sqroot
jsr _peekwr ; get number into WR
jsr _stackdecr ; make room for remainder
lda #16 ; pairs of bits
sta XR ; counter
lda #$0000
sta STACKBASE+0,x ; init remainder
sta STACKBASE+2,x
sta STACKBASE+4,x ; init root
sta STACKBASE+6,x
lp: asl STACKBASE+4,x ; root = root * 2
asl WR ; now shift 2 bits of number into remainder
rol WR+2
rol STACKBASE+0,x
rol STACKBASE+2,x
asl WR
rol WR+2
rol STACKBASE+0,x
rol STACKBASE+2,x
lda STACKBASE+4,x ; copy root into temp
sta YR
lda STACKBASE+6,x ; (a bit shorter than immediate load)
sta YR+2
sec ; +1
rol YR ; temp = temp * 2 + 1
rol YR+2
lda STACKBASE+2,x ; compare remainder with partial
cmp YR+2
bcc next ; skip sub if remainder smaller
bne subtr ; but do it if equal
lda STACKBASE+0,x
cmp YR
bcc next ; same deal
subtr: lda STACKBASE+0,x ; subtract partial from remainder
sbc YR
sta STACKBASE+0,x
lda STACKBASE+2,X
sbc YR+2
sta STACKBASE+2,x
inc STACKBASE+4,x ; no need to increment high word, always zero
next: dec XR
bne lp
rts
.endproc