remove bsb() again - too confusing?

This commit is contained in:
Irmen de Jong
2026-01-06 22:39:04 +01:00
parent 97dade3655
commit bc4470aeda
15 changed files with 19 additions and 65 deletions
-3
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@@ -99,9 +99,6 @@ msb (x)
Get the most significant (highest) byte of the word or long value x
(so for a long value, msb($11223344) is $11, not $33).
bsb (x)
Get the 'bank' byte of the long value x (this is bits 16-23): bsb($00aabbcc) is $aa.
msw (x)
Get the most significant (higher) word of the value x. For all word and byte numbers this will always result in 0.
For a long integer though, it returns the upper 16 bits of x as an uword.