mirror of
https://github.com/zellyn/goapple2.git
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181 lines
7.4 KiB
Plaintext
181 lines
7.4 KiB
Plaintext
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1010 *--------------------------------
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1020 * ROUND FAC USING EXTENSION BYTE
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1030 *--------------------------------
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1040 ROUND.FAC
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1050 LDA FAC
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1060 BEQ RTS.14 FAC = 0, RETURN
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1070 ASL FAC.EXTENSION IS FAC.EXTENSION >= 128?
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1080 BCC RTS.14 NO, FINISHED
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1090 *--------------------------------
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1100 * INCREMENT MANTISSA AND RE-NORMALIZE IF CARRY
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1110 *--------------------------------
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1120 INCREMENT.MANTISSA
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1130 JSR INCREMENT.FAC.MANTISSA YES, INCREMENT FAC
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1140 BNE RTS.14 HIGH BYTE HAS BITS, FINISHED
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1150 JMP NORMALIZE.FAC.6 HI-BYTE=0, SO SHIFT LEFT
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1160 *--------------------------------
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1170 * TEST FAC FOR ZERO AND SIGN
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1180 *
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1190 * FAC > 0, RETURN +1
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1200 * FAC = 0, RETURN 0
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1210 * FAC < 0, RETURN -1
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1220 *--------------------------------
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1230 SIGN LDA FAC CHECK SIGN OF FAC AND
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1240 BEQ RTS.15 RETURN -1,0,1 IN A-REG
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1250 *--------------------------------
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1260 SIGN1 LDA FAC.SIGN
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1270 *--------------------------------
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1280 SIGN2 ROL MSBIT TO CARRY
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1290 LDA #$FF -1
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1300 BCS RTS.15 MSBIT = 1
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1310 LDA #1 +1
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1320 RTS.15 RTS
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1330 *--------------------------------
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1340 * "SGN" FUNCTION
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1350 *--------------------------------
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1360 SGN JSR SIGN CONVERT FAC TO -1,0,1
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1370 *--------------------------------
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1380 * CONVERT (A) INTO FAC, AS SIGNED VALUE -128 TO +127
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1390 *--------------------------------
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1400 FLOAT STA FAC+1 PUT IN HIGH BYTE OF MANTISSA
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1410 LDA #0 CLEAR 2ND BYTE OF MANTISSA
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1420 STA FAC+2
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1430 LDX #$88 USE EXPONENT 2^9
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1440 *--------------------------------
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1450 * FLOAT UNSIGNED VALUE IN FAC+1,2
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1460 * (X) = EXPONENT
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1470 *--------------------------------
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1480 FLOAT.1
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1490 LDA FAC+1 MSBIT=0, SET CARRY; =1, CLEAR CARRY
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1500 EOR #$FF
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1510 ROL
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1520 *--------------------------------
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1530 * FLOAT UNSIGNED VALUE IN FAC+1,2
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1540 * (X) = EXPONENT
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1550 * C=0 TO MAKE VALUE NEGATIVE
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1560 * C=1 TO MAKE VALUE POSITIVE
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1570 *--------------------------------
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1580 FLOAT.2
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1590 LDA #0 CLEAR LOWER 16-BITS OF MANTISSA
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1600 STA FAC+4
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1610 STA FAC+3
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1620 STX FAC STORE EXPONENT
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1630 STA FAC.EXTENSION CLEAR EXTENSION
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1640 STA FAC.SIGN MAKE SIGN POSITIVE
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1650 JMP NORMALIZE.FAC.1 IF C=0, WILL NEGATE FAC
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1660 *--------------------------------
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1670 * "ABS" FUNCTION
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1680 *--------------------------------
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1690 ABS LSR FAC.SIGN CHANGE SIGN TO +
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1700 RTS
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1710 *--------------------------------
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1720 * COMPARE FAC WITH PACKED # AT (Y,A)
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1730 * RETURN A=1,0,-1 AS (Y,A) IS <,=,> FAC
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1740 *--------------------------------
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1750 FCOMP STA DEST USE DEST FOR PNTR
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1760 *--------------------------------
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1770 * SPECIAL ENTRY FROM "NEXT" PROCESSOR
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1780 * "DEST" ALREADY SET UP
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1790 *--------------------------------
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1800 FCOMP2 STY DEST+1
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1810 LDY #0 GET EXPONENT OF COMPARAND
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1820 LDA (DEST),Y
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1830 INY POINT AT NEXT BYTE
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1840 TAX EXPONENT TO X-REG
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1850 BEQ SIGN IF COMPARAND=0, "SIGN" COMPARES FAC
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1860 LDA (DEST),Y GET HI-BYTE OF MANTISSA
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1870 EOR FAC.SIGN COMPARE WITH FAC SIGN
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1880 BMI SIGN1 DIFFERENT SIGNS, "SIGN" GIVES ANSWER
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1890 CPX FAC SAME SIGN, SO COMPARE EXPONENTS
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1900 BNE .1 DIFFERENT, SO SUFFICIENT TEST
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1910 LDA (DEST),Y SAME EXPONENT, COMPARE MANTISSA
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1920 ORA #$80 SET INVISIBLE NORMALIZED BIT
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1930 CMP FAC+1
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1940 BNE .1 NOT SAME, SO SUFFICIENT
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1950 INY SAME, COMPARE MORE MANTISSA
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1960 LDA (DEST),Y
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1970 CMP FAC+2
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1980 BNE .1 NOT SAME, SO SUFFICIENT
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1990 INY SAME, COMPARE MORE MANTISSA
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2000 LDA (DEST),Y
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2010 CMP FAC+3
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2020 BNE .1 NOT SAME, SO SUFFICIENT
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2030 INY SAME, COMPARE REST OF MANTISSA
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2040 LDA #$7F ARTIFICIAL EXTENSION BYTE FOR COMPARAND
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2050 CMP FAC.EXTENSION
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2060 LDA (DEST),Y
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2070 SBC FAC+4
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2080 BEQ RTS.16 NUMBERS ARE EQUAL, RETURN (A)=0
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2090 .1 LDA FAC.SIGN NUMBERS ARE DIFFERENT
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2100 BCC .2 FAC IS LARGER MAGNITUDE
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2110 EOR #$FF FAC IS SMALLER MAGNITUDE
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2120 * <<< NOTE THAT ABOVE THREE LINES CAN BE SHORTENED: >>>
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2130 * <<< .1 ROR PUT CARRY INTO SIGN BIT >>>
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2140 * <<< EOR FAC.SIGN TOGGLE WITH SIGN OF FAC >>>
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2150 .2 JMP SIGN2 CONVERT +1 OR -1
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2160 *--------------------------------
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2170 * QUICK INTEGER FUNCTION
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2180 *
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2190 * CONVERTS FP VALUE IN FAC TO INTEGER VALUE
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2200 * IN FAC+1...FAC+4, BY SHIFTING RIGHT WITH SIGN
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2210 * EXTENSION UNTIL FRACTIONAL BITS ARE OUT.
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2220 *
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2230 * THIS SUBROUTINE ASSUMES THE EXPONENT < 32.
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2240 *--------------------------------
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2250 QINT LDA FAC LOOK AT FAC EXPONENT
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2260 BEQ QINT.3 FAC=0, SO FINISHED
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2270 SEC GET -(NUMBER OF FRACTIONAL BITS)
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2280 SBC #$A0 IN A-REG FOR SHIFT COUNT
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2290 BIT FAC.SIGN CHECK SIGN OF FAC
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2300 BPL .1 POSITIVE, CONTINUE
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2310 TAX NEGATIVE, SO COMPLEMENT MANTISSA
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2320 LDA #$FF AND SET SIGN EXTENSION FOR SHIFT
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2330 STA SHIFT.SIGN.EXT
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2340 JSR COMPLEMENT.FAC.MANTISSA
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2350 TXA RESTORE BIT COUNT TO A-REG
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2360 .1 LDX #FAC POINT SHIFT SUBROUTINE AT FAC
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2370 CMP #$F9 MORE THAN 7 BITS TO SHIFT?
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2380 BPL QINT.2 NO, SHORT SHIFT
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2390 JSR SHIFT.RIGHT YES, USE GENERAL ROUTINE
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2400 STY SHIFT.SIGN.EXT Y=0, CLEAR SIGN EXTENSION
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2410 RTS.16 RTS
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2420 *--------------------------------
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2430 QINT.2 TAY SAVE SHIFT COUNT
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2440 LDA FAC.SIGN GET SIGN BIT
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2450 AND #$80
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2460 LSR FAC+1 START RIGHT SHIFT
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2470 ORA FAC+1 AND MERGE WITH SIGN
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2480 STA FAC+1
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2490 JSR SHIFT.RIGHT.4 JUMP INTO MIDDLE OF SHIFTER
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2500 STY SHIFT.SIGN.EXT Y=0, CLEAR SIGN EXTENSION
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2510 RTS
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2520 *--------------------------------
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2530 * "INT" FUNCTION
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2540 *
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2550 * USES QINT TO CONVERT (FAC) TO INTEGER FORM,
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2560 * AND THEN REFLOATS THE INTEGER.
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2570 * <<< A FASTER APPROACH WOULD SIMPLY CLEAR >>>
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2580 * <<< THE FRACTIONAL BITS BY ZEROING THEM >>>
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2590 *--------------------------------
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2600 INT LDA FAC CHECK IF EXPONENT < 32
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2610 CMP #$A0 BECAUSE IF > 31 THERE IS NO FRACTION
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2620 BCS RTS.17 NO FRACTION, WE ARE FINISHED
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2630 JSR QINT USE GENERAL INTEGER CONVERSION
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2640 STY FAC.EXTENSION Y=0, CLEAR EXTENSION
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2650 LDA FAC.SIGN GET SIGN OF VALUE
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2660 STY FAC.SIGN Y=0, CLEAR SIGN
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2670 EOR #$80 TOGGLE ACTUAL SIGN
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2680 ROL AND SAVE IN CARRY
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2690 LDA #$A0 SET EXPONENT TO 32
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2700 STA FAC BECAUSE 4-BYTE INTEGER NOW
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2710 LDA FAC+4 SAVE LOW 8-BITS OF INTEGER FORM
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2720 STA CHARAC FOR EXP AND POWER
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2730 JMP NORMALIZE.FAC.1 NORMALIZE TO FINISH CONVERSION
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2740 *--------------------------------
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2750 QINT.3 STA FAC+1 FAC=0, SO CLEAR ALL 4 BYTES FOR
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2760 STA FAC+2 INTEGER VERSION
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2770 STA FAC+3
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2780 STA FAC+4
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2790 TAY Y=0 TOO
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2800 RTS.17 RTS
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