86 lines
1.7 KiB
C++
86 lines
1.7 KiB
C++
/* Conformance Test 3.5.1.1: Verification of #if constant expressions */
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int printf(const char *, ...);
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#define FIVE 5
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#define SIX 6
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#if 2 * 8
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#if 4 / 3
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#if 209 - 8
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#if 32760 + 7
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#if (5 == 5)
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#if (2 != 0)
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#define NUM1 (2*8) | (4/3) ^ (209-208) & (32760+7)
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#else
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#define NUM1 5
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#endif
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#else
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#define NUM1 4
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#endif
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#else
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#define NUM1 3
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#endif
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#else
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#define NUM1 2
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#endif
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#else
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#define NUM1 1
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#endif
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#else
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#define NUM1 0
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#endif
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#if (6 < 32767)
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#if (20004 <= 20004)
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#if (59876 > 59875)
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#if (671234 >= 671234)
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#if ((2) && (3))
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#if ((0) || (1))
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#define NUM2 2147 % 3 << 3 >> 2
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#else
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#define NUM2 5
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#endif
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#else
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#define NUM2 4
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#endif
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#else
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#define NUM2 3
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#endif
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#else
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#define NUM2 2
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#endif
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#else
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#define NUM2 1
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#endif
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#else
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#define NUM2 0
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#endif
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#if (-32768)
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#if ~0x7e
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#if !0
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#define NUM3 NUM1 ? NUM2 : 187
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#else
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#define NUM3 2
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#endif
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#else
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#define NUM3 1
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#endif
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#else
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#define NUM3 0
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#endif
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#if (defined(FIVE)) && (defined(SIX)) && (NUM1 == 0x10) && (NUM2 == 4)\
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&& (NUM3 == NUM2)
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int main (void)
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{
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printf ("Passed Conformance Test 3.5.1.1\n");
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}
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#else
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int main (void)
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{
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printf ("Failed Conformance Test 3.5.1.1\n");
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}
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#endif
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