# percent
#   input:  a column of nonnegative numbers
#   output: each number and its percentage of the total

    { x[NR] = $1; sum += $1 }

END { if (sum != 0)
          for (i = 1; i <= NR; i++)
              printf("%10.2f %5.1f\n", x[i], 100*x[i]/sum)
    }