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grep: fix -o match with empty string (suggested by Colin Watson <cjwatson@ubuntu.com>)
function old new delta grep_file 1216 1251 +35 Signed-off-by: Denys Vlasenko <vda.linux@googlemail.com>
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@ -461,15 +461,19 @@ static int grep_file(FILE *file)
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if (found)
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print_line(gl->pattern, strlen(gl->pattern), linenum, ':');
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} else while (1) {
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unsigned start = gl->matched_range.rm_so;
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unsigned end = gl->matched_range.rm_eo;
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unsigned len = end - start;
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char old = line[end];
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line[end] = '\0';
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print_line(line + gl->matched_range.rm_so,
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end - gl->matched_range.rm_so,
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linenum, ':');
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/* Empty match is not printed: try "echo test | grep -o ''" */
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if (len != 0)
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print_line(line + start, len, linenum, ':');
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if (old == '\0')
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break;
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line[end] = old;
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if (len == 0)
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end++;
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#if !ENABLE_EXTRA_COMPAT
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if (regexec(&gl->compiled_regex, line + end,
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1, &gl->matched_range, REG_NOTBOL) != 0)
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@ -98,5 +98,9 @@ testing "grep -o does not loop forever" \
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'grep -o "[^/]*$"' \
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"test\n" \
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"" "/var/test\n"
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testing "grep -o does not loop forever on zero-length match" \
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'grep -o "" | head -n1' \
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"" \
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"" "test\n"
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exit $FAILCOUNT
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