sed: fix "sed n (flushes pattern space, terminates early)" testcase failure

Patch based on work by Dengke Du <dengke.du@windriver.com>

Signed-off-by: Denys Vlasenko <vda.linux@googlemail.com>
This commit is contained in:
Denys Vlasenko 2016-09-01 01:59:11 +02:00
parent 9ff910de6b
commit 76d72376e0
2 changed files with 11 additions and 14 deletions

View File

@ -1300,16 +1300,17 @@ static void process_files(void)
case 'n':
if (!G.be_quiet)
sed_puts(pattern_space, last_gets_char);
if (next_line) {
free(pattern_space);
pattern_space = next_line;
last_gets_char = next_gets_char;
next_line = get_next_line(&next_gets_char, &last_puts_char);
substituted = 0;
linenum++;
break;
if (next_line == NULL) {
/* If no next line, jump to end of script and exit. */
goto discard_line;
}
/* fall through */
free(pattern_space);
pattern_space = next_line;
last_gets_char = next_gets_char;
next_line = get_next_line(&next_gets_char, &last_puts_char);
substituted = 0;
linenum++;
break;
/* Quit. End of script, end of input. */
case 'q':

View File

@ -73,13 +73,9 @@ testing "sed t (test/branch clears test bit)" "sed -e 's/a/b/;:loop;t loop'" \
testing "sed T (!test/branch)" "sed -e 's/a/1/;T notone;p;: notone;p'" \
"1\n1\n1\nb\nb\nc\nc\n" "" "a\nb\nc\n"
test x"$SKIP_KNOWN_BUGS" = x"" && {
# Normal sed end-of-script doesn't print "c" because n flushed the pattern
# space. If n hits EOF, pattern space is empty when script ends.
# Query: how does this interact with no newline at EOF?
testing "sed n (flushes pattern space, terminates early)" "sed -e 'n;p'" \
"a\nb\nb\nc\n" "" "a\nb\nc\n"
}
# non-GNU sed: N does _not_ flush pattern space, therefore c is eaten @ script end
# GNU sed: N flushes pattern space, therefore c is printed too @ script end
testing "sed N (flushes pattern space (GNU behavior))" "sed -e 'N;p'" \