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sed: fix "sed n (flushes pattern space, terminates early)" testcase failure
Patch based on work by Dengke Du <dengke.du@windriver.com> Signed-off-by: Denys Vlasenko <vda.linux@googlemail.com>
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@ -1300,16 +1300,17 @@ static void process_files(void)
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case 'n':
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if (!G.be_quiet)
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sed_puts(pattern_space, last_gets_char);
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if (next_line) {
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free(pattern_space);
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pattern_space = next_line;
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last_gets_char = next_gets_char;
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next_line = get_next_line(&next_gets_char, &last_puts_char);
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substituted = 0;
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linenum++;
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break;
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if (next_line == NULL) {
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/* If no next line, jump to end of script and exit. */
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goto discard_line;
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}
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/* fall through */
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free(pattern_space);
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pattern_space = next_line;
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last_gets_char = next_gets_char;
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next_line = get_next_line(&next_gets_char, &last_puts_char);
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substituted = 0;
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linenum++;
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break;
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/* Quit. End of script, end of input. */
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case 'q':
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@ -73,13 +73,9 @@ testing "sed t (test/branch clears test bit)" "sed -e 's/a/b/;:loop;t loop'" \
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testing "sed T (!test/branch)" "sed -e 's/a/1/;T notone;p;: notone;p'" \
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"1\n1\n1\nb\nb\nc\nc\n" "" "a\nb\nc\n"
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test x"$SKIP_KNOWN_BUGS" = x"" && {
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# Normal sed end-of-script doesn't print "c" because n flushed the pattern
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# space. If n hits EOF, pattern space is empty when script ends.
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# Query: how does this interact with no newline at EOF?
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testing "sed n (flushes pattern space, terminates early)" "sed -e 'n;p'" \
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"a\nb\nb\nc\n" "" "a\nb\nc\n"
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}
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# non-GNU sed: N does _not_ flush pattern space, therefore c is eaten @ script end
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# GNU sed: N flushes pattern space, therefore c is printed too @ script end
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testing "sed N (flushes pattern space (GNU behavior))" "sed -e 'N;p'" \
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