2012-03-27 23:13:14 +00:00
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// Copyright 2009 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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// Package ring implements operations on circular lists.
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package ring
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// A Ring is an element of a circular list, or ring.
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// Rings do not have a beginning or end; a pointer to any ring element
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// serves as reference to the entire ring. Empty rings are represented
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// as nil Ring pointers. The zero value for a Ring is a one-element
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// ring with a nil Value.
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//
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type Ring struct {
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next, prev *Ring
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Value interface{} // for use by client; untouched by this library
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}
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func (r *Ring) init() *Ring {
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r.next = r
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r.prev = r
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return r
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}
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// Next returns the next ring element. r must not be empty.
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func (r *Ring) Next() *Ring {
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if r.next == nil {
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return r.init()
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}
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return r.next
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}
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// Prev returns the previous ring element. r must not be empty.
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func (r *Ring) Prev() *Ring {
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if r.next == nil {
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return r.init()
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}
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return r.prev
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}
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// Move moves n % r.Len() elements backward (n < 0) or forward (n >= 0)
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// in the ring and returns that ring element. r must not be empty.
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//
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func (r *Ring) Move(n int) *Ring {
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if r.next == nil {
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return r.init()
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}
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switch {
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case n < 0:
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for ; n < 0; n++ {
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r = r.prev
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}
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case n > 0:
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for ; n > 0; n-- {
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r = r.next
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}
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}
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return r
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}
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// New creates a ring of n elements.
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func New(n int) *Ring {
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if n <= 0 {
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return nil
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}
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r := new(Ring)
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p := r
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for i := 1; i < n; i++ {
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p.next = &Ring{prev: p}
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p = p.next
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}
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p.next = r
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r.prev = p
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return r
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}
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2014-09-21 17:33:12 +00:00
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// Link connects ring r with ring s such that r.Next()
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2012-03-27 23:13:14 +00:00
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// becomes s and returns the original value for r.Next().
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// r must not be empty.
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//
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// If r and s point to the same ring, linking
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// them removes the elements between r and s from the ring.
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// The removed elements form a subring and the result is a
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// reference to that subring (if no elements were removed,
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// the result is still the original value for r.Next(),
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// and not nil).
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//
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// If r and s point to different rings, linking
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// them creates a single ring with the elements of s inserted
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// after r. The result points to the element following the
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// last element of s after insertion.
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//
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func (r *Ring) Link(s *Ring) *Ring {
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n := r.Next()
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if s != nil {
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p := s.Prev()
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// Note: Cannot use multiple assignment because
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// evaluation order of LHS is not specified.
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r.next = s
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s.prev = r
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n.prev = p
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p.next = n
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}
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return n
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}
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// Unlink removes n % r.Len() elements from the ring r, starting
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// at r.Next(). If n % r.Len() == 0, r remains unchanged.
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// The result is the removed subring. r must not be empty.
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//
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func (r *Ring) Unlink(n int) *Ring {
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if n <= 0 {
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return nil
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}
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return r.Link(r.Move(n + 1))
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}
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// Len computes the number of elements in ring r.
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// It executes in time proportional to the number of elements.
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//
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func (r *Ring) Len() int {
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n := 0
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if r != nil {
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n = 1
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for p := r.Next(); p != r; p = p.next {
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n++
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}
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}
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return n
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}
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// Do calls function f on each element of the ring, in forward order.
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// The behavior of Do is undefined if f changes *r.
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func (r *Ring) Do(f func(interface{})) {
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if r != nil {
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f(r.Value)
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for p := r.Next(); p != r; p = p.next {
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f(p.Value)
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}
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}
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}
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