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https://github.com/autc04/Retro68.git
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82 lines
2.2 KiB
Fortran
82 lines
2.2 KiB
Fortran
! { dg-do run }
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!$ use omp_lib
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integer, allocatable :: a(:, :)
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integer :: b(6, 3)
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integer :: i, j
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logical :: k, l
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b(:, :) = 16
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l = .false.
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if (allocated (a)) STOP 1
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!$omp parallel private (a, b) reduction (.or.:l)
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l = l.or.allocated (a)
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allocate (a(3, 6))
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l = l.or..not.allocated (a)
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l = l.or.size(a).ne.18.or.size(a,1).ne.3.or.size(a,2).ne.6
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a(3, 2) = 1
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b(3, 2) = 1
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deallocate (a)
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l = l.or.allocated (a)
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!$omp end parallel
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if (allocated (a).or.l) STOP 2
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allocate (a(6, 3))
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a(:, :) = 3
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if (.not.allocated (a)) STOP 3
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l = l.or.size(a).ne.18.or.size(a,1).ne.6.or.size(a,2).ne.3
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if (l) STOP 4
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!$omp parallel private (a, b) reduction (.or.:l)
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l = l.or..not.allocated (a)
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a(3, 2) = 1
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b(3, 2) = 1
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!$omp end parallel
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if (l.or..not.allocated (a)) STOP 5
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!$omp parallel firstprivate (a, b) reduction (.or.:l)
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l = l.or..not.allocated (a)
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l = l.or.size(a).ne.18.or.size(a,1).ne.6.or.size(a,2).ne.3
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do i = 1, 6
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l = l.or.(a(i, 1).ne.3).or.(a(i, 2).ne.3)
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l = l.or.(a(i, 3).ne.3).or.(b(i, 1).ne.16)
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l = l.or.(b(i, 2).ne.16).or.(b(i, 3).ne.16)
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end do
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a(:, :) = omp_get_thread_num ()
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b(:, :) = omp_get_thread_num ()
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!$omp end parallel
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if (any (a.ne.3).or.any (b.ne.16).or.l) STOP 6
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k = .true.
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!$omp parallel do firstprivate (a, b, k) lastprivate (a, b) &
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!$omp & reduction (.or.:l)
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do i = 1, 36
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l = l.or..not.allocated (a)
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l = l.or.size(a).ne.18.or.size(a,1).ne.6.or.size(a,2).ne.3
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if (k) then
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do j = 1, 6
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l = l.or.(a(j, 1).ne.3).or.(a(j, 2).ne.3)
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l = l.or.(a(j, 3).ne.3).or.(b(j, 1).ne.16)
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l = l.or.(b(j, 2).ne.16).or.(b(j, 3).ne.16)
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end do
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k = .false.
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end if
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a(:, :) = i + 2
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b(:, :) = i
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end do
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if (any (a.ne.38).or.any (b.ne.36).or.l) STOP 7
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deallocate (a)
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if (allocated (a)) STOP 8
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allocate (a (0:1, 0:3))
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a(:, :) = 0
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!$omp parallel do reduction (+:a) reduction (.or.:l) &
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!$omp & num_threads(3) schedule(static)
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do i = 0, 7
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l = l.or..not.allocated (a)
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l = l.or.size(a).ne.8.or.size(a,1).ne.2.or.size(a,2).ne.4
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a(modulo (i, 2), i / 2) = a(modulo (i, 2), i / 2) + i
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a(i / 4, modulo (i, 4)) = a(i / 4, modulo (i, 4)) + i
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end do
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if (l) STOP 9
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do i = 0, 1
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do j = 0, 3
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if (a(i, j) .ne. (5*i + 3*j)) STOP 10
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end do
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end do
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end
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