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Interrupt handling doesn't use the current running cycles.
Signed-off-by: Adrian.Conlon <adrian.conlon@gmail.com>
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@ -41,7 +41,6 @@ void EightBit::LR35902::ei() {
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}
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int EightBit::LR35902::interrupt(uint8_t value) {
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cycles = 0;
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di();
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restart(value);
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return 4;
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