8.7 KiB
SixtyPical Syntax
This is a test suite, written in Falderal format, for the syntax of the Sixtypical language, disgregarding execution, static analysis, etc.
Note that these example programs are intended to be syntactically correct, but not necessarily sensible programs.
-> Functionality "Check syntax of SixtyPical program" is implemented by
-> shell command "bin/sixtypical --parse-only --traceback %(test-body-file) && echo ok"
-> Tests for functionality "Check syntax of SixtyPical program"
Rudimentary program.
| routine main {
| ld a, 0
| add a, 1
| }
= ok
Program with comments.
| // Welcome to my program.
|
| routine main {
| ld a, 0
| add a, 1 // We are adding the thing.
| }
= ok
Hex literals.
| routine main {
| ld a, $ff
| add a, $01
| }
= ok
Syntax error.
| routine foo (
| ld a, 0
| add a, 1
| )
? SyntaxError
Another syntax error.
| byte glee
| {
| ld a, 0
| add a, 1
| }
? SyntaxError
Extern routines
| routine chrout
| inputs a
| trashes a
| @ 65490
|
| routine chrin
| outputs a
| trashes x
| @ 65487
= ok
Trash.
| routine main {
| trash a
| trash n
| }
= ok
If with not
| routine foo {
| ld y, 0
| cmp y, 10
| if not z {
| inc y
| cmp y, 10
| }
| }
= ok
Repeat loop
| routine foo {
| ld y, 0
| repeat {
| inc y
| cmp y, 10
| } until z
| }
= ok
"While" loop
| routine foo inputs y {
| repeat {
| cmp y, 10
| if not z {
| inc y
| }
| } until z
| }
= ok
Repeat forever
| routine foo inputs y {
| repeat {
| inc y
| } forever
| }
= ok
Repeat with not
| routine foo inputs y {
| repeat {
| inc y
| } until not z
| }
= ok
User-defined memory addresses of different types.
| byte byt
| word wor
| vector routine trashes a vec
| buffer[2048] buf
| pointer ptr
|
| routine main {
| }
= ok
Tables of different types.
| byte table[256] tab
| word table[256] wtab
| vector (routine trashes a) table[256] vtab
|
| routine main {
| }
= ok
Typedefs of different types.
| typedef byte octet
| typedef octet table[256] twokay
| typedef routine trashes a game_routine
| vector game_routine start_game
|
| routine main {
| }
= ok
Can't have two typedefs with the same name.
| typedef byte frank
| typedef word frank
|
| routine main {
| }
? SyntaxError
Explicit memory address.
| byte screen @ 1024
|
| routine main {
| ld a, 100
| st a, screen
| }
= ok
Initialized memory locations.
| byte lives : 3
|
| routine main {
| ld a, lives
| st a, lives
| }
= ok
Cannot have both initial value and explicit address.
| byte screen : 3 @ 1024
|
| routine main {
| ld a, lives
| st a, lives
| }
? SyntaxError
User-defined locations of other types.
| byte table[256] screen @ 1024
| word r1
| word r2 @ 60000
| word r3 : 2000
|
| routine main {
| }
= ok
Initialized byte table.
| byte table[32] message : "WHAT DO YOU WANT TO DO NEXT?"
|
| routine main {
| }
= ok
Can't initialize anything but a byte table with a string.
| word message : "WHAT DO YOU WANT TO DO NEXT?"
|
| routine main {
| }
? SyntaxError
Can't access an undeclared memory location.
| routine main {
| ld a, 0
| st a, lives
| }
? SyntaxError
Can't define two memory locations with the same name.
| byte lives
| byte lives
|
| routine main {
| ld a, 0
| st a, lives
| }
? SyntaxError
Can't shadow the name of a register or a flag.
| byte a
|
| routine main {
| }
? SyntaxError
| byte z
|
| routine main {
| }
? SyntaxError
Can't call routine that hasn't been defined.
| routine main {
| ld x, 0
| ld y, 1
| call up
| call up
| }
? SyntaxError
And you can't call a non-routine.
| byte up
|
| routine main {
| ld x, 0
| ld y, 1
| call up
| }
? SyntaxError
| routine main {
| ld x, 0
| ld y, 1
| call x
| }
? SyntaxError
But you can call a routine that is yet to be defined, further on.
| routine main {
| ld x, 0
| ld y, 1
| call up
| call up
| }
| routine up {
| ld a, 0
| }
= ok
Can't define two routines with the same name.
| routine main {
| inc x
| inc y
| }
| routine main {
| ld x, 0
| ld y, 1
| }
? SyntaxError
Declaring byte and word table memory location.
| byte table[256] tab
|
| routine main {
| ld x, 0
| ld y, 0
| ld a, tab + x
| st a, tab + y
| }
= ok
| word one
| word table[256] many
|
| routine main {
| ld x, 0
| copy one, many + x
| copy word 0, many + x
| copy many + x, one
| }
= ok
Declaring and calling a vector.
| vector routine
| inputs a
| outputs x
| trashes a, x, z, n
| cinv @ 788
|
| routine foo {
| ld a, 0
| }
| routine main {
| with interrupts off {
| copy foo, cinv
| }
| call cinv
| }
= ok
Only vectors can be decorated with constraints like that.
| byte cinv
| inputs a
| outputs x
| trashes a, x, z, n
| @ 788
|
| routine main {
| }
? SyntaxError
Constraints set may only contain labels.
| vector routine
| inputs a
| outputs 200
| trashes a, x, z, n
| cinv @ 788
|
| routine foo {
| ld a, 0
| }
| routine main {
| with interrupts off {
| copy foo, cinv
| }
| call cinv
| }
? SyntaxError
A vector can name itself in its inputs, outputs, and trashes.
| vector routine
| inputs cinv, a
| outputs cinv, x
| trashes a, x, z, n
| cinv @ 788
|
| routine foo {
| ld a, 0
| }
| routine main {
| with interrupts off {
| copy foo, cinv
| }
| call cinv
| }
= ok
A routine can be copied into a vector before the routine appears in the program,
however, it must be marked as such with the keyword forward.
| vector routine
| inputs cinv, a
| outputs cinv, x
| trashes a, x, z, n
| cinv @ 788
| routine main {
| with interrupts off {
| copy foo, cinv
| }
| call cinv
| }
| routine foo {
| ld a, 0
| }
? SyntaxError: Undefined symbol
| vector routine
| inputs cinv, a
| outputs cinv, x
| trashes a, x, z, n
| cinv @ 788
| routine main {
| with interrupts off {
| copy forward foo, cinv
| }
| call cinv
| }
| routine foo {
| ld a, 0
| }
= ok
goto.
| routine foo {
| ld a, 0
| }
| routine main {
| goto foo
| }
= ok
| routine main {
| goto foo
| }
| routine foo {
| ld a, 0
| }
= ok
| vector routine foo
|
| routine main {
| goto foo
| }
= ok
| routine main {
| goto foo
| }
? SyntaxError
| byte foo
|
| routine main {
| goto foo
| }
? SyntaxError
Buffers and pointers.
| buffer[2048] buf
| pointer ptr
| byte foo
|
| routine main {
| copy ^buf, ptr
| copy 123, [ptr] + y
| copy [ptr] + y, foo
| }
= ok
Routines can be defined in a new style.
| typedef routine
| inputs x
| outputs x
| trashes z, n
| routine_type
|
| vector routine_type vec
|
| define foo routine
| inputs x
| outputs x
| trashes z, n
| {
| inc x
| }
|
| routine main
| outputs vec
| trashes a, z, n
| {
| copy foo, vec
| }
= ok
Only routines can be defined in the new style.
| define foo byte table[256]
|
| routine main
| trashes a, z, n
| {
| ld a, 0
| }
? SyntaxError