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cc65/libsrc/common/_time_t_to_tm.s

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;
; Colin Leroy-Mira, 2024
;
; struct tm* __fastcall__ _time_t_to_tm (const time_t t)
;
; Helper to gmtime and localtime. Breaks down a number of
; seconds since Jan 1, 1970 into days, hours and seconds,
; so that each of them fits in 16 bits; passes the
; result to _mktime which fixes all values in the struct,
; and returns a pointer to the struct to callers.
;
.export __time_t_to_tm
.import udiv32, _mktime
.importzp sreg, tmp3, ptr1, ptr2, ptr3, ptr4
.include "time.inc"
.macpack cpu
__time_t_to_tm:
; Divide number of seconds since epoch, in ptr1:sreg,
; by 86400 to get the number of days since epoch, and
; the number of seconds today in the remainder.
; Load t as dividend (sreg is already set by the caller)
sta ptr1
stx ptr1+1
; Load 86400 as divisor
lda #$80
sta ptr3
lda #$51
sta ptr3+1
lda #$01
sta ptr4
lda #$00
sta ptr4+1
; Clear TM buf while we have zero in A
ldx #.sizeof(tm)-1
: sta TM,x
dex
bpl :-
; Divide t/86400
jsr udiv32
; Store the quotient (the number of full days), and increment
; by one as epoch starts at day 1.
clc
lda ptr1
adc #1
sta TM + tm::tm_mday
lda ptr1+1
adc #0
sta TM + tm::tm_mday+1
; Now divide the number of remaining seconds by 3600,
; to get the number of hours, and the seconds in the
; current hour, in neat 16-bit integers.
; Load the previous division's remainder (in ptr2:tmp3:tmp4)
; as dividend
lda ptr2
sta ptr1
lda ptr2+1
sta ptr1+1
lda tmp3
sta sreg
; We ignore the high byte stored in tmp4 because it will be
; zero. We'll zero sreg+1 right below, when we'll have
; a convenient zero already in A.
; Load divisor
lda #<3600
sta ptr3
lda #>3600
sta ptr3+1
; Zero the two high bytes of the divisor and the high byte
; of the dividend.
.if .cpu .bitand CPU_ISET_65SC02
stz ptr4
stz ptr4+1
stz sreg+1
.else
lda #$00
sta ptr4
sta ptr4+1
sta sreg+1
.endif
; Do the division
jsr udiv32
; Store year
lda #70
sta TM + tm::tm_year
; Store hours (the quotient of the last division)
lda ptr1
sta TM + tm::tm_hour
lda ptr1+1
sta TM + tm::tm_hour+1
; Store seconds (the remainder of the last division)
lda ptr2
sta TM + tm::tm_sec
lda ptr2+1
sta TM + tm::tm_sec+1
; The rest of the struct tm fields are zero. mktime
; will take care of shifting extra seconds to minutes,
; and extra days to months and years.
; Call mktime
lda #<TM
ldx #>TM
jsr _mktime
; And return our pointer
lda #<TM
ldx #>TM
rts
.bss
TM: .tag tm