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Fix several errors: The address operator on functions (resulting in a
pointer-to-function type) was not possible. It is redundant but allowed. A cast with a function on the right side resulted in an internal compiler error, since the implicit cast from function to pointer-to-function was missing in this case. An assignment of a function to a void pointer was not possible because the same implicit conversion was missing. git-svn-id: svn://svn.cc65.org/cc65/trunk@482 b7a2c559-68d2-44c3-8de9-860c34a00d81
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@ -198,8 +198,13 @@ unsigned assignadjust (type* lhst, struct expent* rhs)
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* set to the type of the left hand side.
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*/
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{
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/* Get the type of the right hand side */
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/* Get the type of the right hand side. Treat function types as
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* pointer-to-function
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*/
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type* rhst = rhs->e_tptr;
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if (IsTypeFunc (rhst)) {
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rhst = PointerTo (rhst);
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}
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/* After calling this function, rhs will have the type of the lhs */
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rhs->e_tptr = lhst;
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@ -1421,7 +1426,12 @@ static int typecast (struct expent* lval)
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/* Read the expression we have to cast */
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k = hie10 (lval);
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/* Check for a const expression */
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/* If the expression is a function, treat it as pointer-to-function */
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if (IsTypeFunc (lval->e_tptr)) {
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lval->e_tptr = PointerTo (lval->e_tptr);
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}
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/* Check for a constant on the right side */
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if (k == 0 && lval->e_flags == E_MCONST) {
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/* A cast of a constant to something else. If the new type is an int,
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@ -1544,7 +1554,10 @@ static int hie10 (struct expent* lval)
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case TOK_AND:
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NextToken ();
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k = hie10 (lval);
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if (k == 0) {
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/* The & operator may be applied to any lvalue, and it may be
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* applied to functions, even if they're no lvalues.
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*/
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if (k == 0 && !IsTypeFunc (lval->e_tptr)) {
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/* Allow the & operator with an array */
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if (!IsTypeArray (lval->e_tptr)) {
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Error ("Illegal address");
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